a = 2b - c a + c = 2b (a+c)/2 = b b = (a+c)/2
If: a = 2b+c Then: a-c = 2b And: b = (a-c)/2
2s-2b= a+b+c-2b simplified that would be a+c-b.
A = 2b + cSubtract 'c' from each side:A - c = 2bDivide each side by 2:b = 1/2 (A - c)
3ab + 3ac + 2b2 + 2bc = 3a(b + c) + 2b(b + c) = (3a + 2b)(b + c)
2b/c
The LCM of a^2b and b^2c is a^2b^2c
2a + 2b = c subtract 2a from both sides 2a - 2a + 2b = c - 2a 2b = c - 2a divide both sides by 2 (2/2)b = (c - 2a)/2 b = (c - 2a)/2 --------------------
4a + 3c - 2b - c + a - b = 5a - 3b + 2c
3a + 2b = c (find a in terms of b and c)3a +2b -2b = c - 2b3a = c - 2b3a/3 = (c - 2b)/3a = (c - 2b)/3In order to find the value of a, you can give any values to b, and c (except a zero value).
2b + 2c or 2(b + c)
2(b - c)