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∙ 9y ago
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What is the ditloid 3 P C B R Y?
3 Primary Colours - Blue, Red, and Yellow
What does the ditloid 17 Y L mean?
17 yak liquorish
What does the ditloid 1 B E Y stand for?
1 Birthday Every Year
What is the answer to the ditloid 7 Y of BL for B a M?
7 equals years of bad luck for breaking a mirror
How many different ways can you arrange a blue green pink and yellow Easter egg in a row?
1. B g p y2. G p y b3. P y b g4. Y b g p
Can you show me a lot of smiley face things?
:0 :) :( :^} :D :P :B =) =} :/ :S ;) ;P :P :] (y) (.Y.)
What is ditloid 1000 b in a m?
All I can think of is 1000 billionths in a millionth
What is the answer to this ditloid 35 M A in Y at which you may assume the O of P?
"Thirty-five: Minimum Age in Years at which you may assume the Office of President".
What is union probability?
A union probability is denoted by P(X or Y), where X and Y are two events. P(X or Y) is the probability that X will occur or that Y will occur or that both X and Y will occur. The probability of a person wearing glasses or having blond hair is an example of union probability. All people wearing glasses are included in the union, along with all blondes and all blond people who wear glasses. According to Professor Franz Kurfess of California Polytechnic State University, San Luis Obispo, union probability of two independent events A and B can be denoted as: P(A ∪ B) = P(A) + P(B) - P(A ∩ B) = P(A) + P(B) - P(A) * P (B)
Write the equation of the line with a slope of 3 passing through 5 -2?
y=3x+b -2=3*5+b b=-17 y=3x-17
What the notes for happy birthday on steel pan?
h a p p y b I r t h d a y
Two insurance schemes A and B are to be sold An agent has the chance of finding customers as 60 percent for A and 40 percent for B Assuming the sale of A and B is independent find the probability.?
P(X|Y) = P(Y intersection X) / P(Y); where P(X|Y) is probability of event X provided event Y had already occurred P(Y) is probability of event Y happening P(Y intersection X) is probability of events Y & X occurring together Q3.a P(Y): Prob of at least one insurance schemes (A or B) has been sold = 1 - Prob of none of the schemes sold = 1 - (1-Prob of A being Sold)*(1-Prob of B being Sold) // As schemes A & B are independent = 1 - (1-0.6)(1-0.4) = 1 - (0.4)*(0.6) = 1 - 0.24 = 0.76 P(X intersection Y): Prob of at least one insurance schemes (A or B) has been sold AND also scheme 'A' being sold = Prob(A sold) and Prob (B sold) + Prob(A sold) and Prob (B not sold) = 0.6 * 0.4 + 0.6 * (1-0.4) = 0.24 + 0.36 = 0.6 P(X|Y): Prob scheme A has been sold given that at least one insurance scheme has been sold = P(X intersection Y) / P(Y) = 0.6 / 0.76 = 15/19
