0
0 times 0 equals 0. Anything times with 0 would equal 0.
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∙ 14y ago
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The sum of what number and 8 is 0?
Your question is equal to: x + 8 = 0 The answer is x = -8.
Are there values of x for which -x is less than x?
Your question is simply, "solve: -x<x" This becomes "2x>0" which becomes "x>0" That is the final answer
X squared plus 5x?
1. If the question is only to factor this expression:x^2 + 5x = x(x + 5)2. If the question is to solve the equation x^2 + 5x = 0:x^2 + 5x = 0 factor it;x(x + 5) = 0x = 0 orx + 5 =0 subtract 5 to both sides;x = - 5
What is plus 10x-10x equal?
0
How do you solve x equals 0 inequality?
"x equals 0" is an equality, not an inequality. The question is, therefore, not consistent.
Why does cos x - sin x 0?
In general, it does not, so the question is misinformed.
X2 - x - 6?
-4
What is x-1 over x-3 equals 0 Finding intersection with axis?
The only time x-1 over x-3 can be 0 is if the numerator, x-1 is 0 ie if x = 1. The question does not specify which axis.
Is there a possible answer to x squared plus x equals zero?
This is the asker speaking: there is a typo in the question, the real question is: Is there a possible answer to x^2+1=0?
What is x2 - 6x - 7 equals 0?
The answer to the question, as stated, is that it is a quadratic equation in one unknown, x.The solution to the equation is as follows:x2 - 6x - 7 = 0 ie x2 - 7x + x - 7 = 0 or x(x-7) +1(x-7) = 0(x+1)(x-7) = 0 so that x+1 = 0 or x-7 = 0 and so x = -1 or x = 7.
Can anybody answer this hard question Function of x bracket 1 if X is a rational number or 0 if X is an Irrational number?
f(x) = 1 if x is rational f(x) = 0 if x is irrational But there is no specific question about this function. It is a well defined function whose domain is the real numbers and whose codomain consists of the two values, 0 and 1. It is a function with infinitely many discontinuities, and an integral which is 0.
Why is exponent power is one?
Your question is not exactly clear... well maybe one of these helps:1^x = 1 (any x)x^0 = 1 (any x)0^y = 0 (any positive y)
