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What is the approximate freezing point depression of 0.020m aqueous NaBr solution?
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When mercuric iodide is added to an aqueous solution of potassium iodide freezing point is raised why?
Freezing point of the solution will increase. Mercuric Iodide will react with Potassium Iodide to form dipotassium tetraiodomercury. The reaction is given below :2KI + HgI2 = K2[HgI4]This association will decrease the number of ions in the solution as a result of which Van't Hoff Factor (i) will decrease as n decreases from 4 to 3.Now, Freezing point depression when a solute is added to a solvent is given by ΔT = i Kf mClearly now i has decreased from when it was an aqueous KI solution to when HgI is added so ΔT is less now, hence less depression in freezing point which means a higher freezing point.Hence the freezing point of solution will increase.Note: Van't Hoff factor (i) =1+alpha(n-1) where alpha=dissociation degree and n is the no of ions dissociatedHope you understand the reasoning behind it now.
The molecular weight of NaCl determined by studing freezing point depression of its 0.5 percent aqueous solution is 30. What the apparent degree of dissociation of NaCl is?
Theritical MM/ Observed MM = 1 + a (2-1) 58.5/30 = 1+a a = .95 or 95%
What is an aqueos solution?
An *aqueous* solution is formed when a substance is dissolved in water. The term "aqueous" stands for the latin word "aqua" which means water.
How does freezing point get calculated if boiling point of an aqueous solution is given?
F.p.'s and B.p.'s are independent (intensive) properties, you can NOT calculate them.
What is the molar mass of haemocyanin and the freezing point of the solution when an aqueous solution is prepared by dissolving 1.5 grams of haemocyanin a protein obtained from crabs in 0.25 litres of?
Haemocyanins are a group of proteins.
What is the approximate freezing point depression of a 0.050 m aqueous solution?
-0.37 C
Calculate the freezing point depression of an aqueous solution of 0.22 m FeCl3 Assume complete dissociation?
look at Calculate_the_boiling_point_elevation_of_an_aqueous_solution_of_0.0500_m_CaCl2_Assume_complete_dissociationvery similar questionanswer is 1.64 lower than the originial freezing pointif the freezing point is 0 for example the freezing point depression is -1.64
What is the freezing point of an aqueous solution if the boiling point of an aqueous solution is 101.34 degree Celsius?
nobody knows
Compared to the pure water an aqueous solution of calcium chloride has a?
Higher boiling point and a lower freezing point. These are called colligative properties. When a solute is put into solution with the solvent, there is a change in the vapor pressure, osmotic pressure, elevation of the boiling point, and depression of the freezing point.
What is the freezing point of an aqueous 2.65 m calcium chloride CaCl2 solution?
-14.8
When mercuric iodide is added to an aqueous solution of potassium iodide freezing point is raised why?
Freezing point of the solution will increase. Mercuric Iodide will react with Potassium Iodide to form dipotassium tetraiodomercury. The reaction is given below :2KI + HgI2 = K2[HgI4]This association will decrease the number of ions in the solution as a result of which Van't Hoff Factor (i) will decrease as n decreases from 4 to 3.Now, Freezing point depression when a solute is added to a solvent is given by ΔT = i Kf mClearly now i has decreased from when it was an aqueous KI solution to when HgI is added so ΔT is less now, hence less depression in freezing point which means a higher freezing point.Hence the freezing point of solution will increase.Note: Van't Hoff factor (i) =1+alpha(n-1) where alpha=dissociation degree and n is the no of ions dissociatedHope you understand the reasoning behind it now.
What is the freezing point of an aqueous 2.85 m sodium hydroxide (NaOH) solution?
-10.6 c
What is the solution process with water as the solvent?
This solution is called water solution or aqueous solution.
Water is a solvent in a(n) what solution?
'An Aqueous' solution. NB The word 'aqueous' comes from Latin ; 'aqua' meaning 'water'.
What is the freezing point of an aqueous 2.65 m calcium chloride solution?
dT = (i)(Kf)(m) is the equation that can be used to model the freezing point depression. dT represents the change change in temperature. i represents the amount of ions formed from the dissolution of the solute. Kf represents the constant of the freezing point depression of water. m is the molality of the solute in solution. dT = (3)(1.86 degC/m)(2.65m) dT = 14.8 degC 0-14.8 degC = -14.8 degC So the freezing point is -14.8 degrees C. The reason why this value was subtracted from zero is because the presence of a solute lowers the freezing point.
The molecular weight of NaCl determined by studing freezing point depression of its 0.5 percent aqueous solution is 30. What the apparent degree of dissociation of NaCl is?
Theritical MM/ Observed MM = 1 + a (2-1) 58.5/30 = 1+a a = .95 or 95%
What is the freezing point of an aqueous 2.85 m sodium hydroxide NaOH solution The freezing point of pure water is 0.0ºC and Kf of pure water is -1.86ºC m?
-10.6 Celsius
