Find the area and perimeter of a right ABC. The base is 17 cm and height is 21cm.
More information is required to be able to answer this question. The lengths of two sides are not enough to specify it.
A= 268.8cm²
P= 84.94cm
432180. The legs are 441 and 1960.
Find the length of the hypotenuse of a right triangle whose legs are 8 and 15 units in length.
Use the formula for the area of a triangle, which is 0.5 x base x height. Since the 10' and the 15' are at right angles, you can take any of them to be the "base", in which case the other one is the "height".
Lets work it out:- If the legs are 12 and 16 inches, then a rectangle of that size would be 192 square inches in area. As the the diagonal of the rectangle makes two equal triangles (of legs 12 and 16 inches), the area of one of these is half the area of the triangle - 192/2 = 96 square inches.
Using Pythagoras' theorem it is 20 yards in length.
The length of the hypotenuse of a right triangle whose legs measure 45 cm and 60 cm is: 75 cmThe area of the triangle is 1,350 cm2
432180. The legs are 441 and 1960.
Find the perimeter of a right triangle with legs measuring 3 and 4
With sides of 5 and 12, you can make a triangle with any perimeter you want between 24 and 34. If you call them "legs" because they are the sides of a right triangle, then the hypotenuse is 13, and the perimeter is 30.
80 cm
The area of triangle is : 28.0
Find the length of the hypotenuse of a right triangle whose legs are 8 and 15 units in length.
If the legs are 3 and 4 then hypothenuse is 5 (SQRT (3 squared + 4 squared)) = 5) So perimeter is 3 + 4 + 5 = 12
3y - 3
5cm
Draw a right angled triangle with legs of 4cm and 6cm
Use the formula for the area of a triangle, which is 0.5 x base x height. Since the 10' and the 15' are at right angles, you can take any of them to be the "base", in which case the other one is the "height".