A 5 by 3 feet table has an area of 15 ft. squared
Assuming that the table is rectangular, the perimeter is 16 feet; 5 + 5 + 3 + 3
Gg
12 squft
5 feet
Find the area of a rectangle that is 3 feet wide and 5 feet long.
9 feet x 5 feet = 45 sq. feet
15 square feet
Approximately 127.84 square feet.
In a rectangular figure, square feet a generated when you multiply the length of an area by its width. So if a rectangle is 3 feet long by 5 feet wide, the area is 3 x 5 = 15 square feet. If you are dealing with a triangle, the area is half the length by the height... so a triangle 3 feet wise at the base, and 5 feet high, would be 0.5 x (3 x 5) = 0.5 x 15 = 7.5 square feet. If you are dealing with circles, the area is derived from the radius. If the radius is 3 feet, the formula is pi x r2 .... in this case pi x 32 or 9 x pi. Taking pi as 3.14 we get an area of 28.27 sq feet.
it is 15 ft
135 square feet.
They can vary greatly. A typical conference table can be about 3 to 5 feet wide and 10 to 14 feet long.
1 foot 6 inches = 1.5 feetArea of a triangle = .5(base)(height), in this case: .5(3)(1.5), which is 2.25 feet.2.25 feet is equal to 2 feet and 3 inches.
(3 x 31.4) + (3.14 x 25)
A yard is equal to three feet, therefore two yards are equal to 2 x 3 = 6 feet.Given a base of 6 feet and a height of 5 feet, the area of the triangle will be 6 x 5 = 30 square feet.
A table tennis table is ...9 feet (2.74m) long,5 feet (1.525m) wide and2 feet 6 inches (76cm) high... and the net is6 feet (1.83m) long and6 inches (15.25 cm) high.
A cylinder 10 feet high and 5 feet in radius has a surface area of 471.24ft2