Home
Your Answer
Still Have Questions?
Related Questions
What is the width of a rectangle if the area is 34 square yards and the length is 17 yards?
The width is 34/17 = 2 yards
What is the area of a rectangle of 11 inches tall and 17 inches wide?
187 sq. inches (area for a rectangle= length x width
The width of a rectangle is 3 inches less than its length the area of the rectangle is 340 square inches what are the length and width of the rectangle?
Let the width be (x-3) and the length be x: width*length = area (x-3)*x = 340 square inches x2-3x-340 = 0 Solving the above quadratic equation works out as: x = -17 or x = 20 it must be the latter because dimensions can't be negative. Therefore: length = 20 inches and width = 17 inches Check: 20*17 = 340 square inches
What dimension equals area of rectangle equals 221 width equals 17?
If the area is 221 square units and the width is 17 units then the length will be 13 units because 17*13 = 221 square units.
What is the area of a rectangle with a length of 9 meters and a width of 17 meters?
9 meters x 17 meters = 153 square meters.
What is the width of a rectangular floor that has an area of 255 sq ft and a length of 17 ft?
Area = Length*Width so Width = Area/Length = 255/17 ft = 15 feet.
What is the width of a rectangle with length 17 yards and area 59.5 square yards?
It is: 3.5 yards Check: 3.5*17 = 59.5 square yards
What is the weight of rectangle if the length is 3.5 the width is 17 and the height is 1.5?
there is no " weight " on a rectangle. if you mean WIDTH: Keeping in mind that the formula to find an Area of a Rectangle as follow: A= LW ,where A: Area in Square Units, L:Length , W: Width Answer: W=A/L yes their is a "weight" to a rectangle. The formula is W=V(volume)xWD(weight density)
What is the length of a rectangle with the width at 17 and height at 12?
A rectangle is a two dimensional figure. The question gives two dimensions (width and height) - you can't ask for a third dimension of 'length' because two are the limit.If you are looking for the length of the perimeter of this rectangle, it is 58.
The length of a rectangle is 8 cm more than the width find the dimensions of the rectangle if the area is 153 cm square?
Letting x be the length of the rectangle and (x - 8) be the width of the rectangle,x(x - 8) = 153,subtracting 153 from each side, x2 - 8x - 153 = 0,solving for x, (x - 17)(x + 9) = 0, then x = 17 or x = -9,substituting 17 for x, the dimensions of the rectangle are 17cm and 9cm.
What are the different rectangle make with 36ft as the perimeter consider only whole numbers?
Length 1 and Width 17 Length 2 and Width 16 Length 3 and Width 15 Length 4 and Width 14 etc..... get the picture
The area of the square is 17 inches squared choose the correct length of one side?
The area for a four sided shape is length * width = area.We have the area at 17. We know that length = width. We designated length and width as x. Our new equation isx * x = 17, or x2 = 17.Now we have to isolate x.x = sqrt(17).Solving for x, we get x = 4.123.
How do you find the perimeter of a rectangle when the Length is 15 and the width is 8.5?
P=2L+2W Add double the length to double the width 30+17=47
What is the perimeter of a rectangle with 97 inches of length and 17 inches width?
228 inches, what you do is add, 97+97+17+17
What is the area of a rectangle whose diagonal is 17 cm with a perimeter of 460 mm explaining work with answer?
10mm = 1 cm → 460mm = 460 ÷ 10 cm = 46 cm Perimeter = 2 x (length + width) → length + width = perimeter ÷ 2 = 46 cm ÷ 2 = 23 cm → length = 23 cm - width area = length x width → area = (23 - width) x width = 23 x width - width^2 [1] Using Pythagoras: length^2 + width^2 = diagonal^2 → length^2 + width^2 = 17^2 → (23 - width)^2 + width^2 = 17^2 → 23^2 - 46 x width + width^2 +width^2 = 17^2 → 2 x width^2 - 46 x width + 529 - 289 = 0 → 2 x width^2 - 46 x width + 240 = 0 → width^2 - 23 x width + 120 = 0 → 120 = 23 x width - width^2 = area (from [1] above]) → area = 120 cm^2
What is the area of a rectangle with a height of 22 cm and a width of 17 cm?
It is: 22*17 = 374 square cm
What is the perimeter of a rectangle with 50 inches of length and 17 inches width?
It is 2*(50 + 17) = 2*67 = 134 inches.
The width of a rectangle is 3 inches less than its length The area of the rectangle is 340 square inches What are the length and width of the retangle?
Let the length be L, then the width = L-3The area = L x W = L x (L-3) = L2-3Lthe area is 340 which = L2 - 3L, 340 = L2-3L, 340-340=L2-3L-340So, L2-3L-340 =0 Factoring this, (L-20)(L+17) = 0Set L-20 equal to zero, L-20 = 0, L-20+20=+20, L=20so, L=20 inches and width = L-3=20-3=17 inchesL=-17 is not a solution since length can't be negative.Your answer islength = 20 inches, width = 17 inches
What is the length and width of the rectangle if the perimeter is 74 cm and its length is 3 cm less then the width?
Let the length be x -3 and the width be x:- 2(x -3 +x) = 74 2x -6 +2x = 74 4x = 80 x = 20 Therefore: length = 17 cm and width = 20 cm Check: 17 +17 +20 +20 = 74 cm
How many square inhes is 57 inches high by 17 inches wide?
Square inches is a measure of area. This appears to be the area of a rectangle, in which case area = length x width. Area = 57in x 17in = 969in2.
What is the length of a rectangle if the sides are 3 more than twice its width and the perimeter is forty-eight feet what is the width?
length + width = ½ perimeter ie 24', so length = 24 - width length = 2 x width + 3, so 24 - width = 2 x width + 3 ie 21 = 3 x width so width = 7 and length = 17
Bob fenced in a rectangle garden in his yard the length of the rectangle is 7 feet longer than the width and the perimeter is 82 feet what is the width of the rectangle?
since you have 4 sides :- 2 * x & 2 * (x + 7) so 2x+2(x+7)=82 2x+2x+14=82 4x = 68 x = 17 feet The width is 17 feet. Method II: Length + width = half perimeter = 41 ft. Subtract 7 and half the answer gives 17 which is the width. (Add back the 7 and the length turns out to be 24 ft.)
What is the area of a rectangle with a length of 24yd and of 17yd?
24*17 = 408 square yards
Still have questions?
