The width is 34/17 = 2 yards

187 sq. inches (area for a rectangle= length x width

Let the width be (x-3) and the length be x: width*length = area (x-3)*x = 340 square inches x2-3x-340 = 0 Solving the above quadratic equation works out as: x = -17 or x = 20 it must be the latter because dimensions can't be negative. Therefore: length = 20 inches and width = 17 inches Check: 20*17 = 340 square inches

If the area is 221 square units and the width is 17 units then the length will be 13 units because 17*13 = 221 square units.

9 meters x 17 meters = 153 square meters.

Area = Length*Width so Width = Area/Length = 255/17 ft = 15 feet.

It is: 3.5 yards Check: 3.5*17 = 59.5 square yards

there is no " weight " on a rectangle. if you mean WIDTH: Keeping in mind that the formula to find an Area of a Rectangle as follow: A= LW ,where A: Area in Square Units, L:Length , W: Width Answer: W=A/L yes their is a "weight" to a rectangle. The formula is W=V(volume)xWD(weight density)

A rectangle is a two dimensional figure. The question gives two dimensions (width and height) - you can't ask for a third dimension of 'length' because two are the limit.If you are looking for the length of the perimeter of this rectangle, it is 58.

Letting x be the length of the rectangle and (x - 8) be the width of the rectangle,x(x - 8) = 153,subtracting 153 from each side, x2 - 8x - 153 = 0,solving for x, (x - 17)(x + 9) = 0, then x = 17 or x = -9,substituting 17 for x, the dimensions of the rectangle are 17cm and 9cm.

Length 1 and Width 17 Length 2 and Width 16 Length 3 and Width 15 Length 4 and Width 14 etc..... get the picture

The area for a four sided shape is length * width = area.We have the area at 17. We know that length = width. We designated length and width as x. Our new equation isx * x = 17, or x2 = 17.Now we have to isolate x.x = sqrt(17).Solving for x, we get x = 4.123.

P=2L+2W Add double the length to double the width 30+17=47

228 inches, what you do is add, 97+97+17+17

10mm = 1 cm → 460mm = 460 ÷ 10 cm = 46 cm Perimeter = 2 x (length + width) → length + width = perimeter ÷ 2 = 46 cm ÷ 2 = 23 cm → length = 23 cm - width area = length x width → area = (23 - width) x width = 23 x width - width^2 [1] Using Pythagoras: length^2 + width^2 = diagonal^2 → length^2 + width^2 = 17^2 → (23 - width)^2 + width^2 = 17^2 → 23^2 - 46 x width + width^2 +width^2 = 17^2 → 2 x width^2 - 46 x width + 529 - 289 = 0 → 2 x width^2 - 46 x width + 240 = 0 → width^2 - 23 x width + 120 = 0 → 120 = 23 x width - width^2 = area (from [1] above]) → area = 120 cm^2

It is: 22*17 = 374 square cm

It is 2*(50 + 17) = 2*67 = 134 inches.

Let the length be L, then the width = L-3The area = L x W = L x (L-3) = L2-3Lthe area is 340 which = L2 - 3L, 340 = L2-3L, 340-340=L2-3L-340So, L2-3L-340 =0 Factoring this, (L-20)(L+17) = 0Set L-20 equal to zero, L-20 = 0, L-20+20=+20, L=20so, L=20 inches and width = L-3=20-3=17 inchesL=-17 is not a solution since length can't be negative.Your answer islength = 20 inches, width = 17 inches

Let the length be x -3 and the width be x:- 2(x -3 +x) = 74 2x -6 +2x = 74 4x = 80 x = 20 Therefore: length = 17 cm and width = 20 cm Check: 17 +17 +20 +20 = 74 cm

Square inches is a measure of area. This appears to be the area of a rectangle, in which case area = length x width. Area = 57in x 17in = 969in2.

length + width = ½ perimeter ie 24', so length = 24 - width length = 2 x width + 3, so 24 - width = 2 x width + 3 ie 21 = 3 x width so width = 7 and length = 17

since you have 4 sides :- 2 * x & 2 * (x + 7) so 2x+2(x+7)=82 2x+2x+14=82 4x = 68 x = 17 feet The width is 17 feet. Method II: Length + width = half perimeter = 41 ft. Subtract 7 and half the answer gives 17 which is the width. (Add back the 7 and the length turns out to be 24 ft.)

24*17 = 408 square yards

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