Abbreviations:A = Area
p =Perimeter
a = apothem
x = times (as in multiply)
A = 1/2(ap)
A = 1/2 (10.4 x 72)
A = 1/2 (748.8)
A = 374.4 square centimeters
We know that the height of an equilateral triangle equals the product of one half of the side length measure with square root of 3.Since in our regular hexagon we form 6 equilateral triangles with sides length of 16 inches, the apothem length equals to 8√3 inches.
To find the area of a Regular hexagon with side length (x) you need:1. The "radius" of the hexagon. (Just the length from the center to the outside edge.)2. The apothem. (which is only just half of the height of the base.)**If you don't have one or both of these you can't do it.**Steps:1. Make a triangle of the apothem (used as a) and the radius. (r)2. Use the Pythagorean Theorem to find 1 half of the side length.3. Multiply the actual side length by 6.4. Multiply that by a.5. The area is your answer.
The apothem is the radial distance from the middle of the side to the centre of the hexagon. A hexagon is six congruent equilateral triangles joined by adjacent sides. Equilateral triangles can be divided into two equal right angled triangles. The upright of the right angled triangle is effectively the apothem of the original hexagon. Pythagoras now kicks in. The apothem (vertical) is A and half the side length (base) is B, the third (longest) side is C and is the same as the original side length. Pythagoras states A2 + B2 = C2. So by transposition, A = root (C2 - B2). As B = 1/2 C, the apothem A is given by: A = root(C2 - (C/2)2) = root(C2 - C2/4) = root(3C2/4) = C x root(3) / 2 So the apothem of a hexagon is 1/2 x root(3) x the side length.
232.57 square inches.
The radius of a circle inscribed in a regular hexagon equals the length of one side of the hexagon.
If the hexagon has side length s, then the apothem is sqrt(3) * s / 2.
Such a hexagon is impossible. A regular hexagon with sides of 2 cm can have an apothem of sqrt(3) cm = approx 1.73.It seems you got your question garbled. A regular hexagon, with sides of 2 cm, has an area of 10.4 sq cm. If you used your measurement units properly, you would have noticed that the 10.4 was associated with square units and it had to refer to an area, not a length.
5.7735026918962... The formula for the area of a hexagon is A=.5ap, or A=(1/2)ap, where A=area, a=apothem, and p=perimeter. This means that, because the area is 100, 100=.5ap, so 200=ap. Because in a regular hexagon the apothem is equal to the side length, what we are really saying here is that 200=6a2. Therefore, 33.333=a2, or a= about 5.77. This is the side length.
For a regular hexagon, half the side length can be calculated from the apothem via trigonometry: half_side_length = apothem x tan 30° Then: area = apothem x 1/2 x perimeter = apothem x 1/2 x side_length x 6 = apothem x half_side_length x 6 = 24 in x (24 in x tan 30°) x 6 ≈ 1995 sq in
An octagon with a side length of 5.8 cm has an apothem that is approximately 7 cm. The area of such a shape is approx 162.4 sq cm.
We know that the height of an equilateral triangle equals the product of one half of the side length measure with square root of 3.Since in our regular hexagon we form 6 equilateral triangles with sides length of 16 inches, the apothem length equals to 8√3 inches.
It is 679 square metres.
An octagon with a side length of 5.8 cm has an apothem that is approximately 7 cm. The area of such a shape is approx 162.4 sq cm.
It is 665.1 sq inches.
Let s be the length of a side of the hexagon and let h be the the apothem 6(1/2sh) it the area of 3sh.
it aould be 10.8 divided by five ok
regular pentagon area of 12 000 m2 and an apothem of 40 m regular pentagon area of 12 000 m2 and an apothem of 40 m need to figure it out from area 12000 m2