The area is 157 square meters rounded to the nearest whole number.
An oval, or more technically an ellipse, has a long ( major) axis and short (minor axis). If major axis length is a and minor length is b, then area, A is A = pi*a*b /4 where and so the area of half an oval is pi*a*b/8
By taking a coordinate system with origin at the center of the ellipse, and x-axis along the major axis, and y-axis along the minor axis, then the ellipse intercepts the x-axis at -5 and 5, and the y-axis at -2 and 2. So that the equation of the ellipse x2/a2 + y2/b2 = 1 becomes x2/52 + y2/22 = 1 or x2/25 + y2/4 = 1.
first of all, learn how to spell. major* and secondly there isnt a difference. minor sounds like a major and a major sounds like a minor... and learn how to spell minor as well.
A simple question with a horrendously complicated answer. Short of carrying out elliptical integrals, the best I can suggest is the Ramanujan approximation according to which: Perimeter = pi*{3(a + b) - sqrt[10ab + 3(a2 + b2)]} where a and b are the semi-major and semi-minor axes. Substituting a = 15 mm and b = 6 mm gives Perimeter = 69.04 mm. A quick and easy, but roughly approximate method is as follows: The ellipse is between a circle of diameter 30 mm and one of 12 mm. Averaging these two gives a diameter of 21 mm. A circle with a 21 mm diameter has a circumference (perimeter) of 65.97 mm.
As you were copying the question, did you notice the drawing alongside it ? Well, see, that sketch is actually part of the question; anybody who wants to try and answer it needs to see that drawing.
The area is 157 square meters.
The major axes of an ellipse is its longest diameter. The minor axes, on the other hand, is the shortest diameter.
2, major & minor. (Yes, really!)
The area of an ellipse with a major axis 20 m and a minor axis 10 m is: 157.1 m2
The major axis and the minor axis.
The moment of inertia of an ellipse about its major axis (x-axis) is given by the equation I = πab^3/4, where a is the length of the semi-major axis and b is the length of the semi-minor axis of the ellipse.
pi x the minor radius x the major radius
Area = pi*a*b where a and b are the semi-major and semi-minor axes.
It is pi*a*b where a and b are the lengths of the semi-major and semi-minor axes.
Area = pi*a*b where a and b are the semi-major and semi-minor axes.
-- the eccentricity or -- the distance between the foci or -- the ratio of the major and minor axes
Circular segment