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y = x2 - 5x

The integral of [ y dx ] = x3/3 - 5x2/2 + C

At x=0, the integral = 0
At x=5, the integral = 125/3 - 125/2 = -20.8333
At x=6, the integral = 72 - 90 = -18
At x = -2, the integral = -8/3 - 10 = -12.6666

a). from 0 to 5, the area is -20.8333 (20.8333 below the x-axis)

b). from 0 to 6, the area is -18.

c). from -2 to +5, the area is (-20.8333 + 12.6666) = +9.8333

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Q: What is the area of the region between y equals x2 -5x and the x axis a from 0 to5 b from 0 to 6 cfrom-2 to5?
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