You think probable to sodium fluoride , NaF.
The atomic number of fluorine is 9.The atomic number of sodium is 11.
Calcium(C)
Calcium=Ca=Atomic number 20 9+11=20
There is no element whose symbol is An.
Na+ is smaller than Na.
At No(F) + At No(Na) = 20.At No of Calcium = 20.
The atomic number of fluorine is 9.The atomic number of sodium is 11.
Calcium(C)
Calcium=Ca=Atomic number 20 9+11=20
Calcium
There is no element whose symbol is An.
Na+ is smaller than Na.
To find percent composition, you must work with the atomic masses. Look on a periodic chart to find the atomic masses of F and Na. You will find that Na has an atomic mass of 22.990 grams per mole of Na and that F has an atomic mass of 18.998 grams per mole of F. So, add these both together, and that will tell you how much mass NaF will be. NaF will have a mass of 41.988 grams per mole of NaF. Now to take the percent composition of F in NaF, simply divide the mass of F by the mass of NaF. That will give you [18.998/41.988]=.452 which will be about 45%. So your answer is that F has a 45% composition of NaF. PS: Since Na and F only had a stoichiometry of 1 (meaning there is 1 Na and 1 F in the molecule), no multiplication of the atomic masses was necessary when calculating the total mass of the molecule.
The atomic number of a Fluorine (F) atom is 9, meaning it has 9 protons within its nucleus.
fluorine is a non metal element. Atomic number of it is 9.
The number of electrons increases with the atomic number. So the electronegativity increases with the atomic number. Not quite. Electronegativity doesn't consistently increase with atomic number. For example, F is more electronegative than Na, even though Na has a higher atomic number.
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