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velocity is distance traveled per unit of time. If you multiply it by time traveled you get distance traveled.For example if you travel 10 meters in one second (velocity) for 20 seconds (time) you travel 10 x 20 = 200 meters
The answer will vary with the weight/ velocity of the bullet. Using an average velocity 165 gr bullet, a 30-06 rifle zeroed at 200 yds will strike ABOUT 15 inches below line of sight at 350 yds.
Positive velocity will move you 200 miles east in 4 hours traveling at a constant speed.
The cars speeded through the Raceway at a velocity in excess of 200 mi./h
Avg speed =dis/time=2(pi)*100/62.8=10m/s Avg velocity will be 0 since the car ends up back from where it is started ..
200 miles / 4 hours = 50 mph
velocity is distance traveled per unit of time. If you multiply it by time traveled you get distance traveled.For example if you travel 10 meters in one second (velocity) for 20 seconds (time) you travel 10 x 20 = 200 meters
The answer will vary with the weight/ velocity of the bullet. Using an average velocity 165 gr bullet, a 30-06 rifle zeroed at 200 yds will strike ABOUT 15 inches below line of sight at 350 yds.
200
yes p head
200
Positive velocity will move you 200 miles east in 4 hours traveling at a constant speed.
Positive velocity will move you 200 miles east in 4 hours traveling at a constant speed.
The cars speeded through the Raceway at a velocity in excess of 200 mi./h
200
200
Atomic decay is a random phenomenon whose distribution is exponential (generally). Thus if the average lifetime is t0 and you wait a time t, the probability that a single atom decay is p=(1-exp(-t/t0)) Thus if you have N atoms, the average number of atoms that decay in the tine t is <N> = N0 (1-exp(-t/t0)) where N0 is the initial number. naturally in a specific experiment the real number of atoms that decay in a time t will not be exactly <N>, this is only the average number over a potentially infinite number of experiments. However, greater N0, more likely the number of atoms observed in a specific experiment will be near to <N>. In your case <N>=188.1 and the expected deviation is of the order of 13, thus the result could fluctuates with high probability between 200 (that is all decay) and 162 (2 sigma point).