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Al2(SO4)3 + 6KOH --> 2 [Al(OH)3](s) + 3K2SO4

or in excess hydroxide:

Al2(SO4)3 + 8KOH --> 2K+ + 2 [Al(OH)4]-(aq) + 3K2SO4

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12y ago
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13y ago

The answer is:

AlCl3 (Solid) + 3 NaOH (Solution) --> Al(OH)3 (Solid) + 3 NaCl (Liquid)

Forming Aluminum hydroxide and sodium chloride.

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12y ago

AlCl3 (aqueous) + 3NaOH (aqueous) -> Al(OH)3 (solid) + 3NaCl (aqueous)

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12y ago

AlCl3 + 3KOH --> Al(OH)3 + 3KCl

If they are solutions, your net ionic equation is:

Al3+ + 3OH- --> Al(OH)3

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12y ago
2 AlCl3 + 3 Ba(OH)2 <> 2 Al(OH)3 + 3 BaCl2
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8y ago

3K2CO3 +2AlCl3 ------->6KCl + Al2(CO3)3

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11y ago

2AlBr3 + 3K2SO4 -> 6KBr + Al2(SO4)3

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FeaR_-Icy Yt

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3y ago

Easy a

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Q: What is the balanced equation for Aluminum chloride and barium hydroxide gas to form aluminum hydroxide and barium chloride?
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