Ba(OH)2 + 2HNO3 -------> Ba(NO3)2 +2H2O
NaNo3 Cu-4T2
the balanced symbol equation for nitric acid and sodium hydroxideis as follows :potassium hydroxide + nitric acid → potassium nitrate + water.KOH + HNO3 → KNO3 + H2O
Ca(OH)2 + 2HNO3 -> Ca(NO3)2 + 2H2O
Ammonium hydroxide and nitric acid yield ammonium nitrate and water.
Nitric acid reacts with barium hydroxide as expressed in the following reaction: 2HNO3 + Ba(OH)2 => Ba(NO3)2 + 2H2O The reaction products are barium nitrate and water. The barium nitrate is a salt, and in the classic acid-base reaction, the products are a salt and water.
Hn03 + koh > kno3 +h20
NaNo3 Cu-4T2
the balanced symbol equation for nitric acid and sodium hydroxideis as follows :potassium hydroxide + nitric acid → potassium nitrate + water.KOH + HNO3 → KNO3 + H2O
Balanced equation of nitric oxide is no3 2-
Ca(OH)2 + 2HNO3 -> Ca(NO3)2 + 2H2O
Ammonium hydroxide and nitric acid yield ammonium nitrate and water.
Nitric acid reacts with barium hydroxide as expressed in the following reaction: 2HNO3 + Ba(OH)2 => Ba(NO3)2 + 2H2O The reaction products are barium nitrate and water. The barium nitrate is a salt, and in the classic acid-base reaction, the products are a salt and water.
potassium hydroxide is POH and nitric acid is HNO3
Nitric acid: HNO3 (acid) Sodium hydroxide: NaOH (base) This is therefore an acid-base reaction. Acid + Base --> Salt + Water Therefore: HNO3 + NaOH --> NaNO3 + H20 Or: Nitric acid + Sodium hydroxide --> Sodium Nitrate + Water
The chemical equation is: KOH + HNO3-------------→KNO3 + H2O
The balanced equation for Lithium carbonate plus Nitric Acid is: LiCO3 + 2HNO3 --> Li(NO3)2 + CO2 + H2O
The answer is Cr(OH)3(s)+3HNO2(aq)-->Cr(NO2)3(aq)+3H2O(l)