Hn03 + koh > kno3 +h20
the balanced symbol equation for nitric acid and sodium hydroxideis as follows :potassium hydroxide + nitric acid → potassium nitrate + water.KOH + HNO3 → KNO3 + H2O
potassium hydroxide is POH and nitric acid is HNO3
KOH(aq) + HNO3(aq) -> KNO3(aq) + H2O(l) This balanced ionic equation represents the neutralization reaction between potassium hydroxide (KOH) solution and nitric acid (HNO3), forming potassium nitrate (KNO3) and water (H2O).
P2H2OC in other words 2 pottassium H2O(water) and C because oxegen and cardon becomes carbon dixcide which makes up the hydoxide part
When nitric acid reacts with potassium hydroxide, potassium nitrate and water are formed. The balanced chemical equation for this reaction is: HNO3 + KOH → KNO3 + H2O. This is a neutralization reaction.
iron :)
The balanced chemical equation for the reaction between potassium hydroxide (KOH) and nitric acid (HNO3) is 1:1 ratio. Therefore, 3 moles of nitric acid will require 3 moles of potassium hydroxide to neutralize it.
The chemical equation is: KOH + HNO3-------------→KNO3 + H2O
It is impossible to balance that equation.
The reaction between nitric acid (HNO3) and potassium hydroxide (KOH) results in the formation of potassium nitrate (KNO3) and water. The balanced chemical equation for this reaction is: HNO3 + KOH → KNO3 + H2O.
Potassium hydroxide and nitric acid will yield potassium nitrate and water. KOH + HNO3 --> H2O + KNO3
Ammonium hydroxide and nitric acid yield ammonium nitrate and water.