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ok what you need to know to balance this is that phosphorus occours as P4 when you see an equation that just gives elemental phosphorus assume its P4 unless they state otherwise, and oxygen as O2

Tetraphosphorus decoxide will have a formula of P4O10

so we'll need 5 lots of O2 to get 10 on the right hand side and the left hand side, and P4 is already on both sides so that's fine

Your full balanced equation is

P4 + 5O2 <-----> P4O10

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12y ago
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12y ago

_P + _O2 -> _P2O5

P-1 P-2

O-2 O-5

In order to balance this equation, you need to first make the reactant oxygen equal the product oxygen. In order to do that, you must make them equal 10.

_P + 5O2 -> 2P2O5

P-1 P-4

O-10 O-10

Now, you need to make the P's equal. This time, you make the coefficient of the reactant phosphorus 4 in order to make it equal the the product phosphorus.

The answer is:

4P+5O2 -> 2P2O5

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11y ago

They react each other and form phosphoric acid.

The balanced chemical equation is given below.

P2O5(s) + 3 H2O(l) --> 2H3PO4(aq)

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13y ago

i believe it is P2O5

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13y ago

4 p + 5 o2 --> 2 p2o5

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13y ago

4 P + 5 O2 = 2 P2O5

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13y ago

P2O5

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Q: Balanced equation for phosphorous pentoxide and water?
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