Complete combustion is easy. Incomplete combustion is trickier, because there really isn't such a thing as the balanced equation for that, there are several possible balanced equations for that.
2C7H14(liquid) + 21O2(gas) => 14CO2(gas) + 14H2O(gas)
C5H10O + 7O2 ---> 5CO2 + 5H2O
It's a simple combustion reaction that produces only water (H2O) and carbon dioxide (CO2). Don't let the big named organic compound be confusing.
Heptene is C7H14 so the answer is 14.
For 2-heptanol you would get 1-heptene and 2-heptene. The 2-heptene should predominate since the double bond is more substituted (the more substituted a double bond is the more stable it is).
14 1-heptyne 2-heptyne 3-heptyne 3-methyl-1-hexyne 4-methyl-1-hexyne 5-methyl-1-hexyne 4-methyl-2-hexyne 5-methyl-2-hexyne 2-methyl-3-hexyne 3,3-dimethyl-1-pentyne 4,4-dimethyl-1-pentyne 3-ethyl-1-pentyne 3,4-dimethyl-1-pentyne 2,2-dimethyl-3-pentyne
h | h - c- h | h - c- h | c=c-c-c-c=c-c the rest of the h's are common sense to fill in but i dont have space ok, don't think the structure is compatible here. that ethyl group should be on the 4th carbon in the horisontal chain
Heptane is a hydrocarbon molecule which contains 7 carbons and 16 hydrogens. Structurally, it can be a simple chain of the 7 carbons, a circular arrangement of the carbons, or any of a number of branching carbon chains. Chemists try to indicate structure by using abbreviations such as:CH3CH2CH2CH2CH2CH2CH3 (for n-heptane) to demonstrate the simple linear straight chain,the word cyclo- in cycloheptane C7H14 (for cycloheptane, though strictly rather an isomere of heptene C7H14) to indicate a circular arrangement,and structures like CH3CH2CH(CH2CH3)CH2CH3 (for 3-ethyl-pentane) to indicate a branching chain -- in this case, there is a chain of 5 carbons with the central one having a 2-carbon chain branching off. These are hard to show here, but an attempt is:C - C -C- C - C |C - CIn total there are 9 isomeres if heptane (11 enantiomeres) which can be seen in the wikipedia page connected by: Related links, just below this answer field.
Heptene is C7H14 so the answer is 14.
For 2-heptanol you would get 1-heptene and 2-heptene. The 2-heptene should predominate since the double bond is more substituted (the more substituted a double bond is the more stable it is).
For 2-heptanol you would get 1-heptene and 2-heptene. The 2-heptene should predominate since the double bond is more substituted (the more substituted a double bond is the more stable it is).
3-heptene indicates that the third carbon atom in the seven-carbon chain has a double bond with the fourth carbon atom. H3C-CH2-CH=CH-CH2-CH2-CH3
it is a pheromone from cows
The name of 3-heptene gives it away, for alkenes end in -ene. Heptene is a carbon chain of 7 carbons, and alkenes have a double bond between carbons at the noted carbon (3), so this double bond is between C3 and C4, and the chain is otherwise completely hydrogenated. You might write the structure as: CH3CH2CH=CHCH2CH2CH3
It is a mono-alkene: C2H5-CH=CH-C3H7
problem here.... can't form heptene (7 carbon chain) from hexanol (6 carbon chain) without another C-C bond being formed, this can't result from dehydration
M.J ABERCROMBIE has written: 'OXYMERCURATION OF BICYCLO [2,2,1]-2-HEPTENE'
2 geometric isomers: 1)-2) -c-c-ch=ch-c-c-c- if the Hs are both on the same side this is a cis,3-pentene if Hs are opposite to each other(one up other down) it is called trans, 3-pentene isomer
Cis-3-heptene
3-heptene indicates that the third carbon atom in the seven-carbon chain has a double bond with the fourth carbon atom. H3C-CH2-CH=CH-CH2-CH2-CH3