The acid-base reaction of hydrobromic acid, HBr, and calcium hydroxide, Ca(OH)2, forms a salt and water, namely the bromine salt of calcium, CaBr2, and water, H2O. It looks like this: HBr + Ca(OH)2 => CaBr2 + H2O All we need to do to balance the equation is make a couple of small changes: 2HBr + Ca(OH)2 => CaBr2 + 2H2O
Calcium reacts with Hydrobromic acid (HBr in water) forming the Calcium bromide and hydrogen gas but calcium bromide again converted into ions in water.
Ca + 2HBr = CaBr2 + H2
CaCo3+2HBr=CaBr2+Co2+H2o
Ca(OH)2 + 2HBr -> CaBr2 + 2H2O
H+(aq)+OH−(aq)→H2O(l)
1Ca(OH)2 + 2HI ---> 2H2O + 1CaI2
The balanced equation is: Ca(NO3)2 + 2NaOH → Ca(OH)2 + 2NaNO3
Al + NaOH Um this is the "equation" of aluminum and Sodium Hydroxide... Na2CO3(aq) + NaOH (aq) --> NO reaction Sodium carbonate + Sodium hydroxide yields no visible reaction
There is no reaction, therefore no equation!!
The chemical reaction is:HBr + NaOH = NaBr + H2O
Any reaction occur.
H+(aq)+OH−(aq)→H2O(l)
There is no reaction , because of the Common Ion Effect. The Common Ion is the Hydroxide.
Balanced:2 KOH + SO3 ----> K2SO4 + H2O
The balanced chemical equation is: MgO + H2O → Mg(OH)2 The product formed in this reaction is magnesium hydroxide.
H2SO4 + 2KOH = K2SO4 + 2H2O
H3NSO3 + NaOH = NaSO3NH2 + H2O
HOC6H4COOH + NaOH = HOC6H4COONa + H2O
HCl + KOH ==> KCl + H2O
Simplified. 2NaOH + H2SO4 -> Na2SO4 + 2H2O
1Ca(OH)2 + 2HI ---> 2H2O + 1CaI2