MnSO4+Na2CO3
The balanced chemical equation would be K4FeC6N6 + KMnO4 + H2SO4 = KHSO4 + Fe2SO43 + MnSO4 + HNO3 + CO2 + H2O.
I must have the same sheet as you as I have the exact same question. Okay, The RFM of Manganese (Mn) is 54.9 The RFM of MnSO4 4H20 is 223 The percentage of Mn in MnSO4 4H2O is 54.9/223 X 100 and that is 24.6 % 0.1 Moles of MnSO4 4H20 is 223/100 X10 = 22.3 24.6 % (percentage of Mn in MnSO4 4H2O) of 22.3 (0.1 Moles of MnSO4 4H2O) is 5.49g Then you do 5.49g/54.9g (RFM of Mn) which is 0.1 Moles of Mn, which is your answer.
Mn(s) + H2SO4(aq) ------> MnSO4(aq) + H2(g) [molecular] Mn(s) + 2H+(aq) -----> Mn2+(aq) + H2(g) [net ionic]
Various type of salts are formed with H2SO4.. They are:K2SO4 , Na2SO4 , MnSO4 , BaSO4
determine the dissolved oxygen(BOD).iodometryMnSO4+Na2CO3
The balanced chemical equation would be K4FeC6N6 + KMnO4 + H2SO4 = KHSO4 + Fe2SO43 + MnSO4 + HNO3 + CO2 + H2O.
The chemical equation is:Al2(SO4)3 + 3 Mn = 2 Al + 3 MnSO4
MnSO4 aplications in Agriculture
For the anhydrous MnSO4 the mass is 167,61 g.
The Balanced Equation is 2 NaI(s) + 2 H2SO4(aq) + MnO2(s) ® Na2SO4(aq) + MnSO4(aq) + I2(g) + 2 H2O(l)
MnSO4 is the only one that directly reacts with O2 at BOD?With alkaline: MnSO4 + 2OH = MnOH2 +SO44Mn(OH)2 + 2 H20 + O2 = 4 Mn(OH)3
3
Manganese sulfate has an ionic bond.
MnSO4.
Manganous sulfate solution for 1L Dissolve one of the following in 1 L of distilled water: 480 g MnSO4 • 4H2O -or- 400 g MnSO4 • 2H2O -or- 364 g MnSO4 • H2O
Formula: MnSO4