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I must have the same sheet as you as I have the exact same question.

Okay,

The RFM of Manganese (Mn) is 54.9

The RFM of MnSO4 4H20 is 223

The percentage of Mn in MnSO4 4H2O is 54.9/223 X 100 and that is 24.6 %

0.1 Moles of MnSO4 4H20 is 223/100 X10 = 22.3

24.6 % (percentage of Mn in MnSO4 4H2O) of 22.3 (0.1 Moles of MnSO4 4H2O) is 5.49g

Then you do 5.49g/54.9g (RFM of Mn) which is 0.1 Moles of Mn, which is your answer.

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14y ago

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MnSO4.


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Formula: MnSO4


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Is MnSO4 soluble in cold water?

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