The value of the bond angle in XeF2 is 180 degrees.
The bond angle is 180o ,F-Xe-F
90
The bond angles in IF4^- (iodine tetrafluoride) are approximately 90 degrees.
XeO4 is tetrahedral. The total number of valence electrons in the molecule is 32 (6 x 4 oxygens and 8 from the Xe) which when divided equally among the oxygens with a double bond to the Xe gives every O molecule a full outer shell, and the Xe an extended shell. If XeO4 (4-), then each O would be single-bonded to the Xe.
The bond length is equal to the linear distance between the nuclei of the bonding atoms. The bond angle is equal to the angle between any two consecutive bonds in a molecule or ion. Bond angles of molecules and ions are usually determined by using the VSEPR theory.
CO32- is trigonal planar, bond angles are 1200
Any angle; the linear distance between carbon and oxygen is 112 fm.
The bond angles are 120 degrees
90 and 180 are the approximate bond angles.
If it is non polar, the bond angles are as follows:I-P-I bond angles: 120ºBr-P-Br bond angles: 180ºI-P-Br bond angles: 90º
The approximate bond angles in CHClO is 120 degrees.
Urea is sp2 hybridized, so the bond angles are ~120 degrees.
jhi
sp3
your dumb
SeF6 is a regular octahedron , all bond angles are 90 degrees
what is the bond angles of amide ion
Xenon tetraixide
tetrahydrap