No way of knowing w/o knowing the voltage.
It depends on the wattage the fan draws. A simple way to work it out is to use a simple formula. Find where it tells you the wattage and then devide by the house hold voltage and that will give you how much current is being used in amps
The formula you are looking for is W = A x V. Watts = Amps x Volts.
Depends on the wattage of the bulb. Formula is Power (watts) = Voltage * Current (A). Therefore for a 55w bulb, in a 12V car, bulb draws 4.6Amps.
Different appliances have different wattage draws. Without knowing the wattage of the appliance, an answer can not be given.
Take the wattage of the bulb and divide that by the voltage of the bulb. This will give the current the bulb draws. Amps are a measure of charge (electron) at an instant of time through a conductor. In an incandescent bulb the filament is heated by the current and the characteristics of the filament, usually tungsten, is that it gives off light when heated.
It depends on the wattage the fan draws. A simple way to work it out is to use a simple formula. Find where it tells you the wattage and then devide by the house hold voltage and that will give you how much current is being used in amps
Depends on the wattage of the bulb. Formula is Power (watts) = Voltage * Current (A). Therefore for a 55w bulb, in a 12V car, bulb draws 4.6Amps.
The formula you are looking for is W = A x V. Watts = Amps x Volts.
The formula you are looking for is W = A x V. Watts = Amps x Volts.
Different appliances have different wattage draws. Without knowing the wattage of the appliance, an answer can not be given.
(current * voltage) / psu efficiency (5 amps * 19 volt) / ~0.8 = ~118 watts
The amps it draws depends on how big it is. Typically 2-12 amps. Check for a manufacturer's plate that shows the wattage Most of the load in a rice cooker is a resistive heating element, so the amperage will be quite close to the wattage divided by the voltage (220 here).
The inverter draws little current on its own. It is the load that is connected to the inverter. If there were no load on the inverter you could use an ampmeter to determine the no load current. One thing to consider is that a higher wattage inverter would have larger gauge wire which is of lower resistance. This could make the no load current lower for the higher wattage inverter. Bottom line is you would have to measure or have a specification on the no load current.
Power = Voltage x Current P=V.I Power (in Watts) = 110V x 8.70A = 957W (Appx. 1kW) - Neeraj Sharma
Usually a CFL has two ratings. The first is wattage and the second is in mA I suspect the wattage is only the wattage of the bulb itself and the second is the actual current draw of both the light bulb and the ballast. They are not compatible. If you figure the mA and multiply times the voltage you will obtain close to the actual wattage of the combination of the bulb and the ballast. I have a 100 watt Feit BPESL25T which indicates it draws 25 Watts when it actually draws 47.5 Watts. Very close to the mA (400 x 120 VAC =48 Watts) indicated on the base. Almost all CFLs I've tested with my very accurate Fluke RMS meter draw twice the wattage they indicate. Not such a good deal.
Take the wattage of the bulb and divide that by the voltage of the bulb. This will give the current the bulb draws. Amps are a measure of charge (electron) at an instant of time through a conductor. In an incandescent bulb the filament is heated by the current and the characteristics of the filament, usually tungsten, is that it gives off light when heated.
The amperage that a chandelier draws is based on the amount of bulbs and the wattage of the bulbs used in the fixture. Count the amount of bulbs and multiply that number by the wattage of the bulbs. Take this total wattage and use this formula. I = W/E. Amps = Watts/ Volts.