SnBr4 + 2MgO -> SnO2 + 2MgBr2
Tin on its own is a neutral atom but will form cations since it is a metal.
The Answer To Your Question Is.... tin (IV) oxide
In aluminum bromide ( AlBr3) there are two kinds of ions:one cation Al(3+) andthree anions Br(-)
Acidic or basic are notions adequate for compounds.Uranium(IV) is a cation.
Tin (II) Bromide.
Tin (IV) Bromide
Tin (IV) Bromide
SnBr4 + 2MgO -> SnO2 + 2MgBr2
Sn(IV)CO3
Aluminium cation is 3+; bromide anion is Br-. The aluminium bromide is AlBr3.
First of all, the correct formula is SnO2, and the Stock name is tin(IV) oxide.
The name of this cation is tribromanylsulfanium.
Lithium bromide (LiBr) is a compound, not a cation. The cation is Li+.
No, it is is not. A cation is always formed by losing an electron while bromide is an anion formed by gaining an electron. By rahul
Tin II Bromide is SnBr2
2+