4
When an atomundergoesalpha decay, it loses two neutrons (as well as two protons).
The mass does not change much. The Atomic number will increase though.
The mass number decreases by 4 and the atomic number decreases by 2 after alpha decay. This is because an alpha particle consists of 2 protons and 2 neutrons, which are emitted during the decay process.
The change in mass number from 211 to 207 after a decay is due to the emission of an alpha particle, which consists of two protons and two neutrons. When an alpha particle is emitted during radioactive decay, the mass number decreases by 4 and the atomic number decreases by 2.
nuclear decay, such as alpha decay or beta decay.
Alpha decay decreases the atomic number by two. Beta- decay increases the atomic number by one. Beta+ decay decreases the atomic number by one. Gamma decay does not change the atomic number. However, gamma decay is often incidental to a precipitating alpha or beta event that upsets the energy equilibrium in the nucleus, so the two are not unrelated.
Alpha decay has the greatest mass, as it involves the emission of an alpha particle consisting of two protons and two neutrons. This particle has a mass of around 4 atomic mass units.
The correct equation for the alpha decay of Polonium-214 is: 218/84Po -> 214/82Pb + 4/2He This shows the decay of Polonium-214 into Lead-214 and a Helium nucleus, where the atomic number and mass numbers are conserved.
D. All of these change. In alpha decay, an isotope emits an alpha particle, which consists of two protons and two neutrons, leading to a decrease in the atomic number and mass number of the parent isotope. This results in the formation of a new element with a different name, atomic number, and mass number.
Alpha decay decreases the atomic mass of an atom by 4 units and the atomic number by 2 units. This is because an alpha particle, which consists of 2 protons and 2 neutrons, is emitted during the decay process.
During alpha decay, an atom emits an alpha particle, which consists of two protons and two neutrons. As a result, the original atom loses mass equivalent to the mass of the alpha particle released. This loss of mass results in a decrease in the atomic mass of the parent atom, and according to Einstein's equation (E=mc^2), the lost mass is converted into energy, which is released during the decay process.
The atomic number of an atom undergoing alpha decay decreases by 2. Not asked, but answered for completeness, the atomic mass number decreases by 4.