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Assuming the 2 oxidation state of lead.

Pb + 2HNO3 --> Pb(NO3)2 + H2

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12y ago

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What is the chemical equation for reaction between lead nitrate and sulphuric acid?

Lead nitrate + Sulphuric acid ----> Lead sulphate + Nitric acidPb(NO3)2 + H2SO4 ----> PbSO4 + 2 HNO3Warning : Lead sulfate and Nitric acid are toxic. Nitric acid is very reactive and may produce fumes of Nitric oxide when exposed to air.


What is the balanced equation for the reaction of nitric acid on lead?

if you mean lead the metal: Pb + 2H+ --> Pb+2 + H2


Lead nitrate and sulfuric acid?

When lead nitrate is reacted with sulfuric acid, lead sulfate and nitric acid are formed. The balanced chemical equation for this reaction is: Pb(NO3)2 + H2SO4 -> PbSO4 + 2HNO3. This reaction is a double displacement type.


What is the name of the substance formed when the metal 'Lead' reacts with Nitric acid?

In this reaction, a colorless salt, lead nitrate is formed.


Nitric acid plus lead oxide?

lead nitrate and water


What happens when lead nitrate reacts with sulphuric acid?

When lead nitrate reacts with sulfuric acid, lead sulfate and nitric acid are formed. The balanced chemical equation for this reaction is: Pb(NO3)2 + H2SO4 → PbSO4 + 2HNO3. Lead sulfate is a white precipitate that will form in the solution.


What is the balance equation for lead nitrate and hydrochloric acid to form lead chloride and nitric acid?

Pb(NO3)2 (aq) + 2HCl (aq) ----> PbCl2 (s) + 2HNO3 (aq)


What gas evolved when lead11 carbonate reacts with nitric acid?

CO2 gas PbCO3 + 2HNO3 ---> Pb(NO3)2 + H2O + CO2


What does sulfuric acid give out when reacting with lead nitrate?

Let's see. Pb(NO3)2 + H2SO4 --> PbSO4 + 2HNO3 If double displacement, lead sulfate ( a salt ) and nitric acid.


What is the Chemical composition of battery?

the positive plate is Pb the negative is PbO2 and the acid is H2SO4.


What is lead ii carbonate plus nitric acid?

The reaction is:Pb(CO3)2 + 2 HNO3 = Pb(NO3)2 + 2 CO2 + H2O


Reaction of lead oxide with nitric acid?

The actual reaction is: Pb(s) + 4HNO3(aq) -----> Pb(NO3)2(aq) + 2H2O(l) + 2NO2(g) This is interesting for a number of reasons. Since the activity of lead is less than H2, (The Eo for the reduction of Pb2+ to the metal is -0.125 V, compared to the minimum -0.6 V or less that is required) the reaction cannot occur as a single replacement, e.g. Pb(s) + 2HNO3(aq) -----> Pb(NO3)2(aq) + H2(g) does not occur. There are really two reactions at work. 1.) HNO3 oxidizes Pb to form PbO: Pb(s) + 2HNO3(aq) -----> PbO(s) + H2O(l) + 2NO2(g) Lead is oxidized from 0 to +2 and two moles of N are reduced from +5 to +4. This is a redox reaction. 2.) HNO3 then reacts with PbO and to form Pb(NO3)2: PbO(s) + 2HNO3(aq) -----> Pb(NO3)2(aq) + H2O(l) This is a double replacement reaction. This sequence of events is seen (albeit with a change in stoichiometry) for other some other metals as well, most notably copper and silver.