Assuming the 2 oxidation state of lead.
Pb + 2HNO3 --> Pb(NO3)2 + H2
Lead nitrate + Sulphuric acid ----> Lead sulphate + Nitric acidPb(NO3)2 + H2SO4 ----> PbSO4 + 2 HNO3Warning : Lead sulfate and Nitric acid are toxic. Nitric acid is very reactive and may produce fumes of Nitric oxide when exposed to air.
if you mean lead the metal: Pb + 2H+ --> Pb+2 + H2
When lead nitrate is reacted with sulfuric acid, lead sulfate and nitric acid are formed. The balanced chemical equation for this reaction is: Pb(NO3)2 + H2SO4 -> PbSO4 + 2HNO3. This reaction is a double displacement type.
In this reaction, a colorless salt, lead nitrate is formed.
lead nitrate and water
When lead (Pb) is mixed with nitric acid (HNO3), a chemical reaction occurs, resulting in the formation of lead(II) nitrate (Pb(NO3)2) and nitrogen dioxide (NO2) gas. The reaction can be represented by the equation: ( \text{Pb} + 4 \text{HNO}_3 \rightarrow \text{Pb(NO}_3\text{)}_2 + 2 \text{NO}_2 + 2 \text{H}_2\text{O} ). This reaction produces a colorless solution of lead(II) nitrate, which is soluble in water, along with brown nitrogen dioxide gas.
When lead nitrate reacts with sulfuric acid, lead sulfate and nitric acid are formed. The balanced chemical equation for this reaction is: Pb(NO3)2 + H2SO4 → PbSO4 + 2HNO3. Lead sulfate is a white precipitate that will form in the solution.
Pb(NO3)2 (aq) + 2HCl (aq) ----> PbCl2 (s) + 2HNO3 (aq)
CO2 gas PbCO3 + 2HNO3 ---> Pb(NO3)2 + H2O + CO2
Let's see. Pb(NO3)2 + H2SO4 --> PbSO4 + 2HNO3 If double displacement, lead sulfate ( a salt ) and nitric acid.
the positive plate is Pb the negative is PbO2 and the acid is H2SO4.
The reaction is:Pb(CO3)2 + 2 HNO3 = Pb(NO3)2 + 2 CO2 + H2O