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I will assume that the box is moving at a constant speed, so that the frictional force is 70 N. Frictional force is defined as F = mu(the greek letter) times the normal force(in this case, mg). We can figure the normal force to be 9.8 times the 58 kg, which is 568.4 Newtons. So now, we need to figure mu, and to do so, we divide the 70 newton force by the normal force. mu = .123.

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Q: What is the coefficient of kinetic friction between a 58.0 kg box and the horizontal force of 70 N of a floor?
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