NO2
Nitrogen has an oxidation number of -3. Since it is in group 15, it has 5 valence electrons. It wants to have eight, so it will gain three electrons. Electrons are negative, that's why the oxidation number is negative.
The oxidation number for nitrogen can vary depending on the compound it is in. In most cases, nitrogen has an oxidation number of -3, but it can also have oxidation numbers ranging from -3 to +5 in different compounds.
Nitrogen typically has an oxidation state of -3 in its most common compounds, such as ammonia (NH3) or nitrate (NO3-). However, in some compounds like nitrous oxide (N2O) or nitrogen dioxide (NO2), nitrogen can have different oxidation states.
the oxidation number of nitrogen is 5
Nitrogen can exist in oxidation states ranging from -3 to +5. Some common nitrogen compounds with different oxidation states include ammonia (NH3) in the -3 oxidation state, nitric oxide (NO) in the +2 oxidation state, nitrogen dioxide (NO2) in the +4 oxidation state, and nitric acid (HNO3) in the +5 oxidation state.
The most common oxidation state of nitrogen is -3 in compounds like ammonia (NH3) and ammonium (NH4+), but it can range from -3 to +5 depending on the compound.
The oxidation states of nitrogen can range from -3 to +5, with common ones being -3, 0, +3, +4, and +5. The actual oxidation state of nitrogen in a compound depends on its overall charge and the electronegativities of the surrounding atoms.
The oxidation number of nitrogen in most compounds is -1***************2nd Opinion *******************I don't think so. Nitrogen has many oxidation numbers. +5 is pretty common, as found in nitrates. +3 is found in nitrites. -3 is found in ammonia and nitrides. What is the most common? That I don't know.
The minimum oxidation number for nitrogen is -3.
The oxidation number of nitrogen in ammonium nitrite (NH4NO2) is +3. In the ammonium ion (NH4+), nitrogen has an oxidation number of -3 and in the nitrite ion (NO2-), nitrogen has an oxidation number of +3.
The oxidation number of nitrogen in N2 is 0 since it is in its elemental form where the oxidation number is always 0.
The oxidation number of nitrogen in nitrogen dioxide (NO2) is +4. Each oxygen atom in NO2 has an oxidation number of -2, and since the molecule is neutral, the sum of the oxidation numbers must equal zero. Therefore, the oxidation number of nitrogen is calculated as follows: 2(-2) + x = 0, where x represents the oxidation number of nitrogen. Solving for x gives x = +4.