The following answer is correct only if b is the measure of an angle in degrees.
The complement is 90-43 = 47 degrees.
Whatever you do to one side of the equation (equals sign), you must do to the other: 43 - b = 24 ⇒ 43 - b + b = 24 + b ⇒ 43 = 24 + b ⇒ 43 - 24 = 24 + b - 24 ⇒ 19 = b So b is 19.
(A' ∩ B') = (A È B)'
30 is the answer A+ student raynaray
With the information that is available from the question, it is impossible.
Since the angles are complementary, [ A + B = 90 ], so we can substitute (90-B) wherever we see 'A'.The question tells us that [ A - B = 22 ]Make the substitution for ' A ':(90 - B) - B = 2290 - 2B = 22-2B = -682B = 68B = 34A = 56
180
b
complement of c
Whatever you do to one side of the equation (equals sign), you must do to the other: 43 - b = 24 ⇒ 43 - b + b = 24 + b ⇒ 43 = 24 + b ⇒ 43 - 24 = 24 + b - 24 ⇒ 19 = b So b is 19.
X=30 degrees
(A' ∩ B') = (A È B)'
B=26 you just have to isolate the variable, so subtract 17 from 43 because the rule in algebra is that whatever you do to one side, you have to do to the other
The complement of a subset B within a set A consists of all elements of A which are not in B.
30 is the answer A+ student raynaray
P(A given B')=[P(A)-P(AnB)]/[1-P(B)].
In a triangle a/SinA = b/SinB = c/SinC Since angle A = 43 and angle C is 72, angle B = (180) - (72 + 43) = 65 Hence 20/Sin65 = c/Sin72 20/0.9063 = c/0.9510 c = (20 x 0.9510)/0.9063 = 20.9864
67 degrees