Antimony sulfide; sodium oxide; carbonic acid.
Na2S2O3 That's 2 sodiums at 23 each, 2 sulfurs at 32 each, and 3 oxygens at 16 each. 23+23+32+32+16+16+16=158g/mol.
To prepare a 0.1N Na2S2O3 solution, dissolve 24.98 grams of Na2S2O3·5H2O (sodium thiosulfate pentahydrate) in distilled water and dilute to 1 liter in a volumetric flask. This will give you a 0.1N (normal) solution of Na2S2O3.
A white, translucent crystalline compound, Na2S2O3·5H2O, used as a photographic fixing agent and as a bleach. Also called hypo, hyposulfite; Also called sodium hyposulfite. Source: http://www.answers.com/sodium+thiosulfate?gwp=11&ver=2.3.0.609&method=3
To prepare a 0.1 N (normal) solution of sodium thiosulfate (Na2S2O3), first calculate the required mass of Na2S2O3 based on its equivalent weight. For sodium thiosulfate, the equivalent weight is approximately 126.1 g/mol divided by 2, since it can donate two electrons in redox reactions, resulting in about 63.05 g/equiv. Dissolve the calculated mass of Na2S2O3 in distilled water, then dilute to a final volume of 1 liter. Ensure to mix thoroughly for a homogeneous solution.
The molecular formula of sodium thiosulfate is Na2S2O3.
This compound is sodium thiosulphate. S represents +6 oxidation number.
The oxidation number of Sulfur (S) in Na2S2O3 is +2. This is because the overall charge of the compound is zero, and since each Sodium (Na) atom has an oxidation state of +1, the oxidation state of Sulfur must be +2 to balance the charges in the compound.
In Na2S2O3, the oxidation numbers are +1 for sodium (Na), -2 for sulfur (S), and +2 for oxygen (O). This can be determined by considering the overall charge of the compound and known oxidation number rules.
The chemical symbol for sodium thiosulphate (hypo) is Na2S2O3•5H2O. Hope that helps.
The chemical formula for sodium oxide is Na2O. It is an ionic compound and the ions present are Na+ and O2-.
The structure of Na2S2O3, also known as sodium thiosulfate, consists of two sodium ions (Na+), two sulfur atoms (S), and three oxygen atoms (O) in its chemical formula. The compound contains a thiosulfate ion (S2O3 2-) where the central sulfur atom is connected to three oxygen atoms and to a second sulfur atom.
Na2S2O3 That's 2 sodiums at 23 each, 2 sulfurs at 32 each, and 3 oxygens at 16 each. 23+23+32+32+16+16+16=158g/mol.
To prepare a 0.1N Na2S2O3 solution, dissolve 24.98 grams of Na2S2O3·5H2O (sodium thiosulfate pentahydrate) in distilled water and dilute to 1 liter in a volumetric flask. This will give you a 0.1N (normal) solution of Na2S2O3.
first we calculate the molecular weight M.W=158.11 mass of Na2S2O3=M.W*concentration*volume(in litter) for a concentration of 0.001 mass of Na2S2O3=158.11*0.001*1=0.15811 g so we use this mass and continue the volume to be 1 L
Na2S2O3(aq) + 2HCL(aq) => 2NaCl(aq) + S(s) + SO2(g) + H2O(l)
A white, translucent crystalline compound, Na2S2O3·5H2O, used as a photographic fixing agent and as a bleach. Also called hypo, hyposulfite; Also called sodium hyposulfite. Source: http://www.answers.com/sodium+thiosulfate?gwp=11&ver=2.3.0.609&method=3
Sodium thiosulfate