To prepare a 0.1N Na2S2O3 solution, dissolve 24.98 grams of Na2S2O3·5H2O (sodium thiosulfate pentahydrate) in distilled water and dilute to 1 liter in a volumetric flask. This will give you a 0.1N (normal) solution of Na2S2O3.
To prepare a 0.1 N (normal) solution of sodium thiosulfate (Na2S2O3), first calculate the required mass of Na2S2O3 based on its equivalent weight. For sodium thiosulfate, the equivalent weight is approximately 126.1 g/mol divided by 2, since it can donate two electrons in redox reactions, resulting in about 63.05 g/equiv. Dissolve the calculated mass of Na2S2O3 in distilled water, then dilute to a final volume of 1 liter. Ensure to mix thoroughly for a homogeneous solution.
To prepare a 250 ml saturated solution of sodium thiosulphate, start by adding sodium thiosulphate (Na2S2O3·5H2O) to a clean container, gradually mixing it with distilled water until no more solid dissolves and the solution reaches saturation. Typically, this requires adding approximately 80 grams of sodium thiosulphate to the water. Stir the mixture thoroughly and allow it to settle for any undissolved solids to settle at the bottom. Finally, transfer the clear solution to a volumetric flask and make up the volume to 250 ml with distilled water.
To prepare a 50mm glucose solution, you would need to dissolve 9g of glucose in enough water to make 100mL of solution. This would give you a solution with a concentration of 50mm (millimolar).
To prepare a chitosan solution, dissolve chitosan powder in an acidic solution (such as acetic acid or hydrochloric acid) with stirring. Adjust the pH as needed and filter the solution to remove any undissolved particles. The concentration of the chitosan solution can be adjusted by varying the amount of chitosan powder used.
it is very easy to prepare working solution from a stock solution we use the formula for this purpose which is: C1V1 = C2V2 C1 is the concentration of the stock solution V1 required volume from the stock solution C2 concentration of the working solution V2 volume of the working solution
To prepare a 0.01N KBr solution, dissolve 0.74g of KBr in 1 liter of water. This will give you a solution with a molarity of 0.01N for KBr.
To prepare 0.2M solution of anhydrous sodium thiosulfate (Na2S2O3), you dissolve 24.6g of anhydrous Na2S2O3 in distilled water and dilute it to 1 liter. This is the molar mass method, where molar mass of Na2S2O3 is 158.10 g/mol.
first we calculate the molecular weight M.W=158.11 mass of Na2S2O3=M.W*concentration*volume(in litter) for a concentration of 0.001 mass of Na2S2O3=158.11*0.001*1=0.15811 g so we use this mass and continue the volume to be 1 L
To prepare a 0.1 N (normal) solution of sodium thiosulfate (Na2S2O3), first calculate the required mass of Na2S2O3 based on its equivalent weight. For sodium thiosulfate, the equivalent weight is approximately 126.1 g/mol divided by 2, since it can donate two electrons in redox reactions, resulting in about 63.05 g/equiv. Dissolve the calculated mass of Na2S2O3 in distilled water, then dilute to a final volume of 1 liter. Ensure to mix thoroughly for a homogeneous solution.
You do not need especially 25 grams to prepare 1.0 Liter 0.1N Na2S2O3-solution.It depends what substance is used: Na2S2O3 orNa2S2O3•5H2O (more common, called hypo).Molar masses are different, 158.11 g/mol for Na2S2O3 or(158.1 g/mol + 5*18.02 = ) 248.2 g/mol for Na2S2O3•5H2O respectively.To get the 0.10 N solution you'll need 15.8 gram or 24.8 gram respectively, dissolve it togather with 1 gram of disodium carbonate, and add up to 1.0 Liter (freshly boiled) water, let stand overnight and filter on fine grade paper.
To prepare 0.02M sodium thiosulfate solution, weigh out the required amount of sodium thiosulfate pentahydrate (Na2S2O3·5H2O) or anhydrous sodium thiosulfate (Na2S2O3). Dissolve this in distilled water and make up the volume to the desired concentration. Make sure to use a volumetric flask for accuracy and precision in preparing the solution.
To prepare a 0.01N solution of sodium thiosulfate, dissolve 2.48 grams of sodium thiosulfate pentahydrate (Na2S2O3·5H2O) in distilled water and make up the solution to 1 liter. This solution will be approximately 0.01N in strength. Remember to accurately weigh the compound and use a volumetric flask for precise dilution.
To prepare 0.01N sodium thiosulfate per Indian Pharmacopoeia (IP) standards, dissolve 25.3 grams of pure sodium thiosulfate pentahydrate (Na2S2O3·5H2O) in distilled water to make 1000 ml of solution. This solution will have a normality of 0.01N.
If the Na2S2O3 solution were omitted, the appearance of the solution would not change significantly for each kinetic trial. Na2S2O3 is a reagent that acts as a reducing agent and is not directly involved in the appearance of the reaction solution. Its absence would likely affect the reaction rate rather than the visual appearance of the solution.
To prepare a 0.002M sodium thiosulfate solution, dissolve the appropriate amount of sodium thiosulfate pentahydrate (Na2S2O3·5H2O) in distilled water to make the desired volume of solution. Calculate the molarity using the formula M = (mol/L) and adjust as needed. Make sure to accurately measure and mix the components to ensure a homogeneous solution.
Mol.Wt =248.17Molarity =( Wt/ Mol.Wt ) /No:of litres of solution0.1 =( Wt / 248.17) / 0.5Wt =0.1 *0.5*248.17Wt = 12.4085g in 500ml of solution.
To find the amount of Na2S2O3 solution needed, first calculate the moles of AgBr using its molar mass. Then, use the stoichiometry of the balanced equation between AgBr and Na2S2O3 to determine the moles of Na2S2O3 required. Finally, use the molarity of Na2S2O3 to find the volume needed in milliliters.