Not really sure, but if you check some more search engines they mostly say that C4H10 is called Butane. I'm trying to find this out myself! But I think it is Butane.
The compound may be tetra carbon deca-hydride
The chemical formula for butanal is CH3CH2CH2CHO.
The most likely answer is none, because C4H10 is the formula of a saturated hydrocarbon, and such a compound normally reacts with chlorine only by substituting chlorine atoms for some of the hydrogen atoms initially present in the saturated hydrocarbon. Therefore, if four of the hydrogen atoms in each molecule of C4H10 are replaced, the formula of the product would be C4H6Cl4, not C4H10Cl4.
C8H18 is indeed an organic molecule. It is an aliphatic compound, meaning it is composed of carbon hydrogen and it is not aromatic.
The balanced equation is 2 C4H10 + 13 O2 -> 8 CO2 + 10 H2O.
the compound name is atoms.
BUTANE!
Butane is an alkane - C4H10.
yes butance is a pure substance and not a mixture yes butance is a pure substance and not a mixture
C4H10
C4H10(g) is about -126 kJ/mol C4H10(l) is about -147 kJ/mol
LPG or liquefied petroleum gas is a mixture of hydrocarbon gases. The two most common are butane (C4H10) and propane (C3H8).
1 mole C4H10 = 58.1222g = 6.022 x 1023 molecules 11.7g C4H10 x 6.022 x 1023 molecules/58.1222g = 1.21 x 1023 molecules C4H10
The chemical formula for butanal is CH3CH2CH2CHO.
The most likely answer is none, because C4H10 is the formula of a saturated hydrocarbon, and such a compound normally reacts with chlorine only by substituting chlorine atoms for some of the hydrogen atoms initially present in the saturated hydrocarbon. Therefore, if four of the hydrogen atoms in each molecule of C4H10 are replaced, the formula of the product would be C4H6Cl4, not C4H10Cl4.
Butane-C4H10 C4H10 - H C4H9 - ? C4H9 + CHO C4H9CHO
No, different:butane is a compound C4H10brine is a solution of salt (3% - 25%) and water.
It is hard to pinpoint how many carbon atoms are in 2.5g of butane. Roughly, the answer is 1.04 x 10^23 moles. This had to be indicated by figuring out the moles per grams first.