im asking ,,why u asking me again,,isnt this website for answering question how weird..
Fristly drow one line.then bottom of this line 4 types
7493 4-bit asynchronous binary counter with /2 and /8 sections and reset. +----------+ /CLK1 |1 +--+ 14| /CLK0 RST1 |2 13| RST2 |3 12| Q0 |4 7493 11| Q3 VCC |5 10| GND |6 9| Q1 |7 8| Q2 +----------+ [This information is part of the GIICM]
http://ftp.csci.csusb.edu/schubert/tutorials/csci310/f03/dw4bit.pdf
Because that's how Intel designed it. Even though the 8085 is an 8-bit computer, the program counter and stack pointer are 16 bits wide in order to support the address bus, which is also 16 bits wide. In the case of the 8086/8088, the program counter and stack pointer are still 16 bits wide, even though the address bus is 20 bits wide, because the 8086/8088 adds segmentation through the 16 bit segment register which is left shifted by 4.
Add 1 to the value and we will get 100000000. Total 4 bits are being toggled.
Fristly drow one line.then bottom of this line 4 types
Carefuly ! Very Carefully.
4
it has for bit or states for its output
it has for bit or states for its output
You do it by studying, and doing your homework by yourself instead of trying to get someone else to do it for you.
7493 4-bit asynchronous binary counter with /2 and /8 sections and reset. +----------+ /CLK1 |1 +--+ 14| /CLK0 RST1 |2 13| RST2 |3 12| Q0 |4 7493 11| Q3 VCC |5 10| GND |6 9| Q1 |7 8| Q2 +----------+ [This information is part of the GIICM]
I wants to know the advantages of 4 Bit BCD/Binary UP/DOWN
This is the the thing for micro controller . Normally in microcontroller operation we used to give the clock pulse to connected circut chips .One chip requires 4 clock pulse .then the second, third vise versa . By which the pulse starts from 4 is for first chip, 8 is for second chip(4+4), 16(4+8+4) is for thir.............Like that depending upon the requirement of the clock signal for chips we used to tell 16 bit counter , 32 bit counter ect.
http://ftp.csci.csusb.edu/schubert/tutorials/csci310/f03/dw4bit.pdf
try this link: " http://www.play-hookey.com/digital/johnson_counter.htm"
One jk flip-flop with j=k=1 should be added to the system so that it's modulus becomes 16 instead of 8.