[He]2s^22p^6
The electron configuration of oxygen in the oxide ion (O2-) is 1s2 2s2 2p6 (equivalent to the configuration of a neon atom), as the oxide ion has gained two extra electrons compared to a neutral oxygen atom.
[He]2s^22p^6
[He]2s^22p^6
Oxide - O2- electronic configuration of oxygen atom: 1s2, 2s2 2p4. electronic configuration of oxygen ion: 1s2, 2s2 2p6. phosphate - PO43-
The noble gas that is isoelectronic with the oxide ion O2 is neon (Ne). Both the oxide ion O2 and the neon atom have 10 electrons.
Neon, if you are talking about an oxygen ion.
The element, oxygen, is in group 16, period 2 of the periodic table. Thus its electron configuration is 1s2 2s2 2p4. Oxide's ionic state is O2-, so to get its electron configuration we just need to add two electrons to the old one. That yields 1s2 2s2 2p6.
The formula for the oxide ion is O2-, and the formula for the nitrate ion is NO3-.
O2- is the formula for oxide ion. The negative symbol indicates the presence of anions and 2 represents the oxidation state.
O=oxygen atom, o2=oxygen molecule, o2-=oxide, o22-=peroxide, o2-=superoxide, o3=ozone.
Oxide ion (O²⁻) has the electron configuration of a noble gas neon (Ne), which is 1s² 2s² 2p⁶.
Oxide ion (O2-) is isoelectronic with neon. Both species have the same number of electrons, which is 10.