H3PO4 (aq) + H2O (l) ---> 2H3O+ (aq) + PO4-3 (aq)
donor acid + acceptor base ---> conjugate acid + conjugate base
the answer above is wrong
to form a conjugate, the ion H2PO4 - must lose a hydrogen ion H+
i.e
H2PO4 - -H+ = HPO4 2-
(conjugate base)
No, the equation is: HPO4-2 → H+ + PO4-3 The HPO4-2 and PO4-3 are conjugate acid base pairs.
H2po3 ^-1
The conjugate base of H2PO3- ion is HPO3-2 ion.
The conjugate base for HPO4^2- is H2PO4^-.
The conjugate base of HC2O4 is C2O4^2-.
No, the equation is: HPO4-2 → H+ + PO4-3 The HPO4-2 and PO4-3 are conjugate acid base pairs.
H2po3 ^-1
The conjugate base of H2PO3- ion is HPO3-2 ion.
The conjugate base for HPO4^2- is H2PO4^-.
The conjugate base of HC2O4 is C2O4^2-.
The conjugate base of HAsO4^2- is H2AsO4-.
The conjugate base and conjugate acid for HS04 is: Conjugate acid is H2SO4 Conjugate base is SO42
The conjugate base for HSO4- is SO4^2-.
The conjugate base of HCO3 is CO3^2-.
The conjugate base of HCO3- is CO32-. Conjugates always differ by one H+. A conjugate base has one fewer H+, while a conjugate acid has one more H+.
The conjugate base of H2CO3 is HCO3-. Nope, itsHSO3-
O2 2-O^2-The conjugate base for HS04 is SO42.