The price is approx. 100 000 US $.
At 10°C, the solubility of strontium bromide (SrBr₂) in water is approximately 3.5 grams per 100 grams of water. This means that you can dissolve about 3.5 grams of strontium bromide in 100 grams of water at this temperature.
SrCl2 Strontium (Sr) = 87.62 grams/mol 2 Chlorine (Cl) = 70.9 grams/mol ----------------------------------------------------add Strontium chloride = 158.52 grams/mol ============================
4.563 grams are in 1 mole of Strontium Nitrate.
To find the mass of 1.15 mol of strontium sulfate, you first need to calculate the molar mass of strontium sulfate, which is 183.68 g/mol. Then, multiply the molar mass by the number of moles: 1.15 mol * 183.68 g/mol = 211.22 grams. Therefore, the mass of 1.15 mol of strontium sulfate is 211.22 grams.
Well, isn't that a happy little question! If half a kilogram costs 40p, that means each gram costs 0.08p (40p divided by 500g). So, for 100 grams, it would be 8p (0.08p multiplied by 100g). Just remember, mistakes are just happy accidents in the world of math!
To find the cost of 100 grams at £1.40 per kilogram, first convert kilograms to grams: 1 kg equals 1000 grams. Therefore, £1.40 per kg translates to £0.0014 per gram. For 100 grams, the cost would be 100 grams × £0.0014/gram = £0.14.
$120 for 100 grams
The cost of 100 grams of titanium can vary depending on the supplier, quality, and market conditions. Typically, titanium prices range from $3 to $6 per gram, so 100 grams of titanium may cost between $300 to $600.
After 65.2 days, half of the original amount of strontium-85 will remain, so 5 grams will be left.
$530 for 100 grams. And it would be "Beryllium's"...apostrophe.
the answer to this question is 4.9$ for 100 grams of pure bromine.
100 grams is one tenth of a kilogram (kilo is the prefix for 1000) so 850 /10 = 85 Answer: 100 grams costs 85 monetary units