Want this question answered?
There are 1000 grams in one kilogram. Therefore, 3 kilograms is equal to 3 x 1000 = 3000 grams.
cotton
Assuming the spring obeys Hooke's Law, we can use the formula F = kx, where F is the force, k is the spring constant, and x is the displacement. Since the spring is stretched by 2cm (or 0.02m) when supporting a 1kg load, we can calculate the spring constant k. With a 1kg load, F = 1kg * 9.8m/s^2 = 9.8N. Therefore, k = F / x = 9.8N / 0.02m = 490N/m. Now, for a 3kg load, F = 3kg * 9.8m/s^2 = 29.4N. Using the spring constant k = 490N/m, we can rewrite F = kx as 29.4N = 490N/m * x. Solving for x, we find that the spring will be stretched by 0.06m (or 6cm) when supporting a 3kg load.
The answer for this question is that the 300 kilogram because it ways more than the 3 kilometer your welcome
3L of water = 3kg 1L = 1kg = 2.2 lb. (us)
R38.50
There are 1000 grams in one kilogram. Therefore, 3 kilograms is equal to 3 x 1000 = 3000 grams.
65
1kg - dry ash 2kg - wet ash 3kg - ash.
Sulfur
cotton
3kg is greater than 3g 1kg = 1000g
Ek mishri hai jo gili ho to 2kg, sukhi ho to 1kg aur jal jaaye to 3kg ka weight hota hai.
Assuming the spring obeys Hooke's Law, we can use the formula F = kx, where F is the force, k is the spring constant, and x is the displacement. Since the spring is stretched by 2cm (or 0.02m) when supporting a 1kg load, we can calculate the spring constant k. With a 1kg load, F = 1kg * 9.8m/s^2 = 9.8N. Therefore, k = F / x = 9.8N / 0.02m = 490N/m. Now, for a 3kg load, F = 3kg * 9.8m/s^2 = 29.4N. Using the spring constant k = 490N/m, we can rewrite F = kx as 29.4N = 490N/m * x. Solving for x, we find that the spring will be stretched by 0.06m (or 6cm) when supporting a 3kg load.
sulphur.now answer this for me :D2a-8b-3abif a=-3, if b=6the answer is annoying but whatever :)
Chintu ki sahasikta to avashyak hai. :)
3 x $2.50 = $7.50