The formula you are looking for is I = W/E. Amps = Watts/Volts.
208 v three-phase supplies are an option for American properties, because the line to neutral voltage is 120 v.
A 208 v three-phase system has 120 v between each live wire and the neutral. It is used in the USA as an alternative to the 120/240 v single-phase system, offering 50% more power for the same current.
The reactance is jwL or 2xpix60x0.1 = 37.7 ohms The current with 208 v is 208/37.7 or 5.52 amps. This assumes that the inductor can take the current without saturating, because if it saturates the current might be higher and it might get quite hot.
That is 20.8 kVa but a 208 v single phase supply is very rare. 208 v is usually three-phase, with 120v between neutral and the live wires.
Vologases V of Parthia died in 208.
I have 12 amps 208/3/60 what would the amps be @ 440/3
To calculate the current (in amps) drawn by a 3-phase heater, you can use the formula: [ \text{Current (I)} = \frac{\text{Power (P)}}{\sqrt{3} \times \text{Voltage (V)}} ] For a 10.6 kW heater at 208 volts, the calculation would be: [ I = \frac{10,600 , \text{W}}{\sqrt{3} \times 208 , \text{V}} \approx 27.8 , \text{amps} ] Thus, the heater will draw approximately 27.8 amps.
in a circuit of pure Resistance (r), IE. voltage source (12 v DC battery) and pure resistance (a light bulb). the voltage (v) and current (i) will be in phase. by adding capacitors and/or inductors to the circuit V and I will be pulled out of phase.
Assuming it is a 208-volt line voltage (as normal in 3-phase) the phase voltage is that divided by sqrt(3), or 120 volts. Each phase has to supply 10 kW so the current on each phase is 83.3 amps.
This 480-v three-phase transformer probably has a 208-v three-phase secondary which has 120 v from each line to neutral. In that case the primary current is 0.433 times as much as the secondary current, so 100 amps in the secondary means 43.3 amps in the primary.
Assuming you can get a three-phase 230 v supply, which has 133 v between neutral and each live, the full-load current assuming a 30% increase for power-factor and efficiency considerations would be 120 amps. In Europe the standard three-phase supply is 400 v. In the US three-phase supplies are normally 208 v or 480 v and an alternative option is a 240/480 v split-phase (single-phase) supply.
A source of 208 volts can be obtained from any two legs of a three phase four wire 208 volt system. The two legs are classed as single phase 208 volts. The lead tags can be L1-L2, L2-L3, or L3-L1 all of which will give you 208 volts. Any of these lead tags to the grounded star point (wye) will give you 120 volts.