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What is the volume of 10.9 mol of helium at STP?
The volume of 10.9 mol of helium at STP is 50 litres.
What is the density of Cl2 gas at STP?
what is the volume of a balloon containing 50.0 moles of O2 gas at a pressure of 15.0 atm at 28 degrees
What is the density at STP of (H2S) in grams per liter?
At standard temperature and pressure (STP), the density of hydrogen sulfide (H₂S) is approximately 1.363 grams per liter. This value can be calculated using the molar mass of H₂S, which is about 34.08 g/mol, and the ideal gas law, considering that one mole of gas occupies 22.414 liters at STP. Therefore, the density is derived by dividing the molar mass by the volume at STP.
What volume does 0685 mol of gas occupy at stp?
At standard temperature and pressure (STP), one mole of an ideal gas occupies 22.4 liters. Therefore, to find the volume occupied by 0.685 mol of gas at STP, you can multiply the number of moles by the volume per mole: 0.685 mol × 22.4 L/mol = 15.34 liters. Thus, 0.685 mol of gas occupies approximately 15.34 liters at STP.
What is the vapour density of the gas if 5.6dm3of a gas weighs 60g at S.T.P?
The molar volume of a gas at STP (standard temperature and pressure) is 22.4 L/mol. To calculate the molar mass of the gas, you can use the formula: Molar mass = (mass of gas / volume of gas) x molar volume at STP. In this case, with a mass of 60g and a volume of 5.6 dm3, the molar mass would be 60g/5.6dm3 x 22.4L/mol = 240 g/mol. Vapour density is calculated as 2 x molar mass, so in this case the vapour density would be 480 g/mol.
At stp the density of ccl4 vapours in g l will be neatest to?
At STP, the molar volume of any ideal gas is 22.4 L/mol. To find the density of CCl4 vapor at STP, we need to calculate its molar mass. CCl4 has a molar mass of 153.8 g/mol, so the density of CCl4 vapor at STP would be 153.8 g/mol divided by 22.4 L/mol, which equals approximately 6.86 g/L.
What is the volume of 2.22 mol of o2 at STP?
1mol of a gas occupies 24 dm3 at STP, so 2.2mol X 24 mol/dm3 =52.8dm3 or 5280cm3
The volume of 1mole of hydrogen bromide at STP is 22.4 liters The gram-formula mass of hydrogen bromide is 80.9 grams per mole What is the density of hydrogen bromide at STP?
The molar volume of a gas at STP is 22.4 liters/mol. The molar mass of hydrogen bromide is 80.9 g/mol. Therefore, the density of hydrogen bromide at STP is 80.9 g/mol / 22.4 L/mol = 3.61 g/L.
Calculate the density of nitrogen gas, in grams per liter, at STP?
At Standard Temperature and Pressure (STP), which is defined as 0 degrees Celsius (273.15 Kelvin) and 1 atmosphere pressure, the molar volume of an ideal gas is approximately 22.4 liters/mol. The molar mass of nitrogen gas (N₂) is approximately 28.02 grams/mol. To calculate the density (D) of nitrogen gas at STP, you can use the ideal gas law: � = Molar mass Molar volume at STP D= Molar volume at STP Molar mass � = 28.02 g/mol 22.4 L/mol D= 22.4L/mol 28.02g/mol � ≈ 1.25 g/L D≈1.25g/L Therefore, the density of nitrogen gas at STP is approximately 1.25 grams per liter.
What volume (in milliliters) of oxygen gas is required to react with 4.03 g of Mg at STP?
2Mg + O2 ==> 2MgO Balanced Equation4.03 g Mg x 1 mole Mg/24.3 g = 0.166 moles Mg present in 4.03 g Mg.moles O2 required = 0.166 moles Mg x 1 mole O2/2 moles Mg = 0.083 moles O2 needed.At STP 1 mole occupies 22.4 L, thusVolume of O2 required = 0.083 moles x 22.4 L/mole = 1.56 L x1000 ml/L = 1859 mlsSince 4.03 g has only 3 significant figures, the correct answer should be 1860 milliliters.
What is the volume of 10.9 mol of helium at STP?
The volume of 10.9 mol of helium at STP is 50 litres.
What volume of oxygen is needed to react with a solid sulfur to form 3.5L of SO2?
1 mole of gas occupies 22.4 liters at STP. Therefore 3.5/22.4 = 0.15625 moles of SO2. There are thus 0.15625 moles of O2 needed to react with solid sulfur because S + O2 ---->SO2. 0.15625 moles of oxygen occupies 0.15625 x 22.4 liters = 3.5 liters O2 required.
What is the density of carbon dioxide CO2 at STP if 1 mole occupies 22.4 L Report answer in grams per liter gL?
Density of CO2 at STP = 44.01 g/mol divided by the 22.4 liters. 1.96 grams/Liter
How many grams would 2350 L of O2 gas at STP weigh?
To find the weight of 2350 L of O2 gas at STP, you would first need to calculate the moles of gas using the ideal gas law. Then, use the molar mass of O2 to convert moles to grams. The molar mass of O2 is 32 g/mol, so you would multiply the moles by 32 g/mol to find the weight in grams.
What is the density of Cl2 gas at STP?
what is the volume of a balloon containing 50.0 moles of O2 gas at a pressure of 15.0 atm at 28 degrees
What is the density at STP of (H2S) in grams per liter?
At standard temperature and pressure (STP), the density of hydrogen sulfide (H₂S) is approximately 1.363 grams per liter. This value can be calculated using the molar mass of H₂S, which is about 34.08 g/mol, and the ideal gas law, considering that one mole of gas occupies 22.414 liters at STP. Therefore, the density is derived by dividing the molar mass by the volume at STP.
What is the density of CO2 gas at STP?
The density of CO2 gas at standard temperature and pressure (STP) is approximately 1.977 g/L. This value is derived from the molar mass of carbon dioxide (44.01 g/mol) divided by the molar volume at STP (22.4 L/mol). The calculation is as follows: 44.01 g/mol / 22.4 L/mol = 1.977 g/L. This density value is useful in various applications, such as in gas laws and stoichiometry calculations.
