0
What else can I help you with?
What is the volume of 84.6 grams of helium at stp?
The volume of any gas at STP (standard temperature and pressure) is 22.4 L/mol. The molar mass of helium is 4.0026 g/mol. So, 84.6 grams of helium would be 84.6/4.0026 = 21.1 mol. Therefore, the volume of 84.6 grams of helium at STP would be 21.1 mol * 22.4 L/mol = 472.64 L.
What volume does 0685 mol of gas occupy at stp?
At standard temperature and pressure (STP), one mole of an ideal gas occupies 22.4 liters. Therefore, to find the volume occupied by 0.685 mol of gas at STP, you can multiply the number of moles by the volume per mole: 0.685 mol × 22.4 L/mol = 15.34 liters. Thus, 0.685 mol of gas occupies approximately 15.34 liters at STP.
What is the volume of 19.87 mol of ammonium chloride NH4Cl at STP?
The volume is 695,85 cm3.
What is the volume of 19.87 mol of ammonium chloride (NH4Cl) at STP?
The volume is 695,62 cm3.
What does avagadros law say about a gas at STP?
1 mol of any gas has a volume of 22.4 L at STP
What is the volume of 84.6 grams of helium at stp?
The volume of any gas at STP (standard temperature and pressure) is 22.4 L/mol. The molar mass of helium is 4.0026 g/mol. So, 84.6 grams of helium would be 84.6/4.0026 = 21.1 mol. Therefore, the volume of 84.6 grams of helium at STP would be 21.1 mol * 22.4 L/mol = 472.64 L.
What is the mass of 43.7 L of helium at STP?
The mass of 43,7 L of helium at STP is 7.8 g.
What is the volume in milliliters of 0.0100 mol of ch4 gas at stp?
The volume of 0.0100 mol of CH4 gas at STP (Standard Temperature and Pressure) is 224 mL. This is based on the ideal gas law and the molar volume of a gas at STP, which is 22.4 L/mol. Converting this to milliliters gives 224,000 mL/mol.
What volume does 0685 mol of gas occupy at stp?
At standard temperature and pressure (STP), one mole of an ideal gas occupies 22.4 liters. Therefore, to find the volume occupied by 0.685 mol of gas at STP, you can multiply the number of moles by the volume per mole: 0.685 mol × 22.4 L/mol = 15.34 liters. Thus, 0.685 mol of gas occupies approximately 15.34 liters at STP.
What is the volume at STP for 0.44 mol C2H6?
The volume of 0.44 mol of C2H6 gas at standard temperature and pressure (STP) is approximately 9.9 L. This is based on the molar volume of a gas at STP, which is around 22.4 L/mol.
What is the volume of 2 mol of oxygen?
The molar volume of a gas at standard temperature and pressure (STP) is 22.4 L/mol. Therefore, the volume of 2 moles of oxygen gas at STP would be 2 moles * 22.4 L/mol = 44.8 L.
What is the volume of 19.87 mol of ammonium chloride NH4Cl at STP?
The volume is 695,85 cm3.
What is the volume of 19.87 mol of ammonium chloride (NH4Cl) at STP?
The volume is 695,62 cm3.
What is the volume of 19.87 mol of ammonium chloride NHÁCl at STP?
To find the volume of 19.87 mol of NH₄Cl at STP (standard temperature and pressure), we can use the ideal gas law. At STP, 1 mol of gas occupies 22.4 L. Therefore, 19.87 mol of NH₄Cl will occupy 19.87 mol x 22.4 L/mol = 445.888 L.
What does avagadros law say about a gas at STP?
1 mol of any gas has a volume of 22.4 L at STP
At STP what is the volume of 150g of ozone O3?
At standard temperature and pressure (STP), the molar volume of a gas is approximately 22.4 L. To find the volume of 150g of ozone (O3) at STP, you would first convert the mass of ozone to moles, then use the molar volume to find the volume.
How do you calculate the volume in liters of 1.50 mol Cl2 at stp?
To calculate the volume of a gas at STP (Standard Temperature and Pressure), you can use the ideal gas law equation: PV = nRT. At STP, the pressure is 1 atm, the temperature is 273 K, and the molar volume of an ideal gas is 22.4 L/mol. Plugging in the values, you can calculate the volume of 1.50 mol of Cl2 at STP.
