The mass of 43,7 L of helium at STP is 7.8 g.
The molar volume of a gas at STP (Standard Temperature and Pressure) is 22.4 L. Ethane gas has a molar mass of 30.07 g/mol. Therefore, the mass of ethane gas in a 5.00 L vessel at STP can be calculated as (5.00 L / 22.4 L) * 30.07 g/mol.
At STP, the molar volume of any ideal gas is 22.4 L/mol. To find the density of CCl4 vapor at STP, we need to calculate its molar mass. CCl4 has a molar mass of 153.8 g/mol, so the density of CCl4 vapor at STP would be 153.8 g/mol divided by 22.4 L/mol, which equals approximately 6.86 g/L.
To calculate the mass of FeO2 produced, we first need to find the number of moles of O2 using the ideal gas law: PV = nRT. At STP, 1 mole of gas occupies 22.4 L, so 50.0 L of O2 is 50.0/22.4 = 2.23 moles. The balanced equation for the reaction will tell you the stoichiometry needed to calculate the mass of FeO2 produced.
The sample with the greatest mass at STP would be the one with the highest molar mass, as 1 mole of any substance at STP occupies the same volume (22.4 L). Among the given options, the sample with Cl2 gas (molar mass = 70.9 g/mol) would have the greatest mass.
Density of CO2 at STP = 44.01 g/mol divided by the 22.4 liters. 1.96 grams/Liter
The volume of any gas at STP (standard temperature and pressure) is 22.4 L/mol. The molar mass of helium is 4.0026 g/mol. So, 84.6 grams of helium would be 84.6/4.0026 = 21.1 mol. Therefore, the volume of 84.6 grams of helium at STP would be 21.1 mol * 22.4 L/mol = 472.64 L.
The weight of 75.0 L of helium depends on the temperature and pressure at which it is measured. At standard temperature and pressure (STP), which is 0°C and 1 atmosphere, the molar mass of helium is 4.0 grams per mole. Using the ideal gas law, we can calculate the weight by multiplying the molar mass of helium by the number of moles, which is the volume divided by 22.4 L (molar volume at STP). However, if the temperature and pressure are not at STP, additional information is needed to determine the weight.
The volume is 0.887 L.
The molar volume of a gas at STP (Standard Temperature and Pressure) is 22.4 L. Ethane gas has a molar mass of 30.07 g/mol. Therefore, the mass of ethane gas in a 5.00 L vessel at STP can be calculated as (5.00 L / 22.4 L) * 30.07 g/mol.
At STP, the molar volume of any ideal gas is 22.4 L/mol. To find the density of CCl4 vapor at STP, we need to calculate its molar mass. CCl4 has a molar mass of 153.8 g/mol, so the density of CCl4 vapor at STP would be 153.8 g/mol divided by 22.4 L/mol, which equals approximately 6.86 g/L.
To calculate the mass of helium, you would need to know the density of helium (0.1785 g/L at 0°C and 1 atm). You can use the formula: mass = density x volume. In this case, mass = 0.1785 g/L x 6.3 L = 1.125 g.
Helium weighs about 1/7 the weight of air. Air weighs about 1.2 g / L. Helium weighs about 0.17 g / L. 10mL of Helium would weigh about 0.0017 grams.
- molar mass: 34,08 g- density: 1,363 g/cm3Mass of H2S: 1,363 x 9,36 = 12,758 g34,08--------------------------1 mol12,758-------------------------xx = 0,374 moles
The molar volume of a gas at STP is 22.4 liters/mol. The molar mass of hydrogen bromide is 80.9 g/mol. Therefore, the density of hydrogen bromide at STP is 80.9 g/mol / 22.4 L/mol = 3.61 g/L.
The molar volume of any ideal gas at standard temperature and pressure (STP) is 22.4 L/mol. Converting 39.6 dm3 to liters gives 39.6 L. To find the mass of argon gas, we calculate the number of moles using the ideal gas equation (PV = nRT) and then multiply by the molar mass of argon.
To calculate the mass of FeO2 produced, we first need to find the number of moles of O2 using the ideal gas law: PV = nRT. At STP, 1 mole of gas occupies 22.4 L, so 50.0 L of O2 is 50.0/22.4 = 2.23 moles. The balanced equation for the reaction will tell you the stoichiometry needed to calculate the mass of FeO2 produced.
Molar mass of propane = 44 g/mole ... 100 / 44 = 2.727 moles one mole occupies 22.4 L at STP .... 22.4 x 2.727 = 50.91 L