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Five
An object will float in water if it has less density than the water. You can calculate the density of the object by dividing its mass by its volume. For comparison, the density of water is: * 1 gram / cubic centimeter * 1 kilogram / liter * 1000 kilograms / cubic meter
An object with an overall density of less than 1 gram per cubic centimetre will float in water if it is designed to displace its own weight in water (Archimedes's Law). This means shaping the object until the volume it occupies is at least the same as an equivalent volume of water. This is the reason why ships built of steel, which has a density greater than water, float.
it will float when its density ( mass per unit volume) is less than that of water (1 gram/cc)
It floats
The density is 0,78 g/cm3.
Five
Object A, 500g/5g/cm3 = 100 cm3 Object B, 650g/65g/cm3 = 10 cm3 Object A displaces more water.
An object will float in water if its density is lower than water which means that for an object to float, its density needs to be less than ~1 gram/centimeter^3,
it depends on the density of the object and the density of the liquid that it's in. if the density of the object is greater than the density of the liquid, then the object will sink. if the density of the object is lesser than the density of the liquid, the object will float.
2.5 ml/g
If an object floats in water, we can immediately conclude that it is less dense than the water. So, we've already gained a bit of information. But can we learn more? Yes. We can further "ballpark" our estimate of the object's density through additional observation and deduction. About how much of the object is submerged? If, say, 75 percent of the object is under water, we can then say that its relative density -- that is, its specific gravity -- is about 0.75. In other words, it has a density of 0.75 grams per milliliter or, equivalently, 0.75 grams per cubic centimeter. (Note that the density of water is 1.00 gram per milliliter.) But can we do better? I think so. If we measure the volume of water displaced by the object when it is placed into the container of water, we can calculate the weight of the object, because its weight will be equal to the weight of the water it displaces. If the floating object displaces, say, 100 milliliters of water, then we know it weighs 100 grams, because, as noted above, the density of water is one gram per milliliter. But we're not done. To calculate an object's density, we must know its volume as well as its mass. From the measurement above, we know the object's weight , but we don't know its volume, mainly because of its irregular shape. But if we carefully push the object completely under water, it will displace an amount of water equal to its volume. Let's say that when we submerge the object fully, it displaces 130 milliliters of water. We therefore conclude that its volume is 130 milliliters, which is equal to 130 cubic centimeters. Since the object weighs 100 grams and has a volume of 130 cubic centimeters, its density is 100 grams/130 cubic centimeters = 0.769 g/cm3.
An object will float in water if it has less density than the water. You can calculate the density of the object by dividing its mass by its volume. For comparison, the density of water is: * 1 gram / cubic centimeter * 1 kilogram / liter * 1000 kilograms / cubic meter
The density of water is 1 gram per cm3 .
An object with an overall density of less than 1 gram per cubic centimetre will float in water if it is designed to displace its own weight in water (Archimedes's Law). This means shaping the object until the volume it occupies is at least the same as an equivalent volume of water. This is the reason why ships built of steel, which has a density greater than water, float.
If the titanium in bicycle frame displaces 0.314 L of water and has a mass of 1.41 kg, the density of the titanium in gcm-3 or gram per cubic centimeter is approximately 4.49. This is based on the formula that density is equivalent to mass divided by volume.
waters density it 1 gram per cubic centimeter. the formula for density is Mass of object divided by its volume