density=mass divided by the volume 12g divided by 27 the volume = 0.4
Methanol, CH4O, has a molar mass of 32g (12g+4.0g+16g)* *note this is only rounded to two sig figs, since the mass of elements are usually rounded to the tenths place. Next, simply use dimensional analysis: 1ml/22.4L X 32g. you should get the right answer by doing the steps shown above.
Move the decimal three place to the left. start at 12.0g ---> 1.2 -----> 0.12 -----> end with 0.012kg
Wiki doesn't do your homework, so it is time to get busy. OH yeah that's what i said oh yeah u tokd him/her (whoever asked this question)
Use the molar masses for sodium (23g/mol) carbon (12g/mol), hydrogen (1g/mol) and oxygen (16g/mol). Add them together in the amounts indicated by the subscripts. Multiply the 3mol by this number and you have your mass in grams!(values are approximate, a good chemistry textbook will have more accurate values).
1.00g of Carbon = 12g/mol 1.00g x 1mol/12g = .0833 mol/C .0833 mol of C x (6.02 x 10^23/1 mol of Carbon) x 6 electrons/1 C atom = 3.01 x 10^23 3.01 x 10^23 protons x -1.602 x 10^-19 (1 electron) = -48220.2 Coulombs OR -4.8 x 10^4
Density = mas/volume = 12 g/27 cc = 0.44... recurring grams per cubic centimetre.
Density = mass ÷ volume = 12g ÷ 3cm3 = 4 g/cm3
Density = Mass/Volume = 12/8 = 1.5 grams per cm3
Density = Mass/Volume = 12/13 g/ml = 0.923 g/ml approx.
Density = grams/cm^3 (cc) 3 cm^3 = 27 cm^3 Density = 12 grams/27 cm^3 = 0.4 grams/cm^3 ----------------------------
The density of the solid is about 0.86 g/cm3
12g
12g
Molecular weight of CO2 is about 44g (12g Carbon + 32g Oxygen *2 atoms Oxygen). So that means if you are presented with 44g CO2, that means there's 12g Carbon.
What you do find the volume by multiplying the height the width and the length So... 3x2x1=6 Then you divide the mass by the volume m/v= 12 / 6 So... The answer is 2cm3
96 g
The molecular weight of sodium hydroxide is 40g/mol. To get the amount of moles, you have to divide the weight by molecular mass. 12g / 40 is 0.3 moles. This is 300 millimoles.