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What is the density of a mineral with a mass of 41.2 g and a volume of 8.2 cm3?
Wiki User
∙ 12y ago
Density is found by dividing mass by volume.
D=M/V
D=41.2g/8.2cm3
D=5.02439g/cm3
With the significant figures being at 2 because of 8.2cm3, the answer is 5.0g/cm3
Wiki User
∙ 12y ago
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What is the density of a substance that has a mass of 7.9g and a volume of 4.2 cm square?
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Volume of sphere in cubic inches = CDXII = 412 Formula for finding volume of sphere = 4/3*pi*radius3 In order to find the radius we must make the radius the subject of the formula. 4/3*pi*radius3 = 412 4*pi*radius3 = 412*3 radius3 = 412*3 divided by (4*pi) radius3 = 98.35775483 radius = 4.616039703 inches, done by cube rooting both sides of the formula. Therefore the radius of a sphere of 412 cubic inches is 4.616 inches, correct to three decimal places. Check that the answer is correct by substituting the answer into the formula which should out as 412 square inches.
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The factors of 412 are: 1 2 4 103 206 412
Factors of 412?
The factors of 412 are: 1 2 4 103 206 412
What is 412 divisible by?
412 is divisible by 1, 2, 4, 103, 206, 412.
What is 412 and divide1059.18?
412 and divide1059.18 = 0.38898015445910983
