Around 17.8.
I did this with cossin, but check the answer with a calculator
Using Pythagoras, Diagonal2 = 322 + 162 = 162*(4 + 1) = 162*5 So diagonal = 16*sqrt(5) = 35.7771 ft (to 4 dp)
38.42 feet.
43.26661530556787
The dimensions given appear to describe a rectangular box, with 3 separate pairs of rectangles: 4X8 -> Diagonal is 8.944 ft 4X12 -> Diagonal is 12.649 ft 8X12 -> Diagonal is 14.422 ft
Two adjacent sides of a square and the diagonal joining their ends froms a right angle triangle. The legs of the triangle are 10 ft each and the diagonal is the hypotenuse. By pythagoras, diagonal = sqrt(102 + 102) = 10*sqrt(2) = 14.142 ft (to 3 dp).
Diagonal = 18.867 feet.
36.8782 ft
20 ft
46.648 ft
The diagonal of a rectangle 8 feet by 12 feet is √208 feet, or about 14 feet 5.06 inches.
By Pythagoras, (Diagonal)2 = 362 + 562 = 1296 + 3136 = 4432 sq ft So diagonal = +sqrt(4432) = 66.75 ft
(Diagonal)2 = (36)2 + (26)2 = 1,972Diagonal = sqrt(1,972) = 44.4072 (rounded)
18.9 feet
18.9 feet
Assuming that the measurements refer to a rectangle, the diagonal would be sqrt(272 + 122) = sqrt(729 + 144) = sqrt(873) = 29.55 ft (to 2 dp)
The diagonal is 7.21 feet.
The diagonal measurement of an 8 ft square is: 11.31 feet.