Use Pythagoras' theorem:-
502+302 = 3400 and the square root of this is the length of the diagonal which is about 58.309 feet to 3 dp
46.648 ft
The diagonal of a rectangle 8 feet by 12 feet is √208 feet, or about 14 feet 5.06 inches.
Since the rectangle has right angles, you can use Pythagoras' Theorem in this case.
Use Pythagoras' therorem to find the diagonal of the rectangle which is 12 times the sq rt of 13
The diagonal is 7.21 feet.
The diagonal is 45.61 feet.
46.648 ft
Sqrt(282 + 402) = a whisker under 48 ft 10 in
Diagonal = 36.9 feet
Using Pythagoras: 462+282 = 2900 and the square root of this is the diagonal which is about 53.852 feet rounded to 3 decimal places
235 Feet
116.6 feet
36.8782 ft
14.42 feet.
25.6125 (rounded)
Using Pythagoras' theorem it works out as 20 times the square root of 5 which is about 44.721 feet to three decimal places.
That would be 34 feet.