That would be 34 feet.
overweight
about 22-30 inches I should say.
42.2 P = 2L + 2W P = 7.6 + 34.6
we know,perimeter of rectangle = 2 * ( l+b) perimeter= 2 *(45+30) = 2 * 75 =150 cm
by measure distance/time like kilometer/second if i want to go from point 1 to point 2 fare from point 1 by 30 kilometer in one hour that is mean ( my velocity is 30 kilometer/second )
32.311
Since the rectangle has right angles, you can use Pythagoras' Theorem in this case.
Assuming that the 40 and 30 refer to sides of a rectangle and not to any of the infinite number of other possible shapes, the answer is 50.
The diagonal of a rectangle with the length of 30 yd and the width of 30 yd is approximately 42.43 yd
Use Pythagoras' theorem:- 502+302 = 3400 and the square root of this is the length of the diagonal which is about 58.309 feet to 3 dp
"X" = .66
The diagonal is approximately 38.42 feet.
A square with a 30-inch diagonal measurement has sides of 21.21 inches in length.
38.42 feet.
The diagonal will be the hypotenuse of a right triangle with legs 30 and 34 feet So its length is the square root of (34^2+ 30^2 )
302+482=3204 squareroot(3204) Answer=56.60388679
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