INR B increments the B register as an 8-bit value.
INX B increments the BC register as a 16-bit value.
Lxi h,xx50 mov a,m inx h mov b,m mvi ,ffh inr c sub b jnc xx08 add b inx h mov m,c inx h mov m,a hlt
In order to add 32 bit numbers in the 8085, you need to add them 8 bits at a time, tracking the carrys between each add. LXI B,first_number LXI H,second_number LXI D,result LDAX B ;first byte - no carry in ADD M STAX D INX B; point to next byte INX D INX H LDAX B ;second byte - carry in ADC M ;note the ADC instead of ADD STAX D INX B; point to next byte INX D INX H LDAX B ;third byte - carry in ADC M STAX D INX B; point to next byte INX D INX H LDAX B ;fourth - carry in ADC M STAX D
03ABH in the 8085 is ... INX B XRA E
no answer
what is the difference between utilization category A and B of MCCB's
100
b-tree
The main difference is in between grade A,B & C IS THE CARBON CONTAIN OF THE MATERIALS.
one has .. and one has . its unequal
LXI H, 4150 ; Point to data LXI B, 0000 ; Initialize hundreds= 0, Tens=0 MOV A, M ; Get hex data to A LOOP: SUI 64 JC LOOP 1 INR B ; hundreds= hundreds+1 JMP LOOP LOOP 1: ADI 64 ; if subtracted extra, add it clear carry flag LOOP 2: SUI 0A JC LOOP 3 INR C ; Tens=tens+1 JMP LOOP 2 LOOP 3: ADI 0A ; If subtracted extra, add it again INX H ; A = Units MOV M, B ; store hundreds MOV B, A ; Combine Tens in C & MOV A, C ; Units in A to form a RLC ; Single 8-bit number RLC RLC RLC ADD B INX H MOV M, A ; Store tens & Units HLT
one is A and one is B
There are a few differences between a and b. A is a vowel and b is a consonant. A and b both have different sounds when pronounced.