It's
P=I^2 * R
P=V^2 / R
Both are derived from Ohm's Law (V=I*R) are are equivalent.
The formula P = I^2R relates power (P), current (I), and resistance (R), indicating the power dissipated in a resistor. On the other hand, the formula P = V^2/R relates power (P), voltage (V), and resistance (R), representing the power dissipated across a resistor. The former formula deals with power in terms of current, while the latter formula expresses power in terms of voltage.
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False. The closer you are to the epicentre, the smaller the time difference between the arrival of P and S-waves.
The distance between a seismic station and the earthquake epicenter is determined from the S-P interval, which is the time difference between the time of arrival of the first P wave and the first S wave.
Your standing on it! P-waves travel faster than S-waves through the Earth. As such the further away a seismometer station is from the epicentre of an Earthquake, the larger the difference between arrival times will be. By the same logic this means that the closer you get to the epicentre, the smaller the difference in arrival time will be until your at the epicentre when the difference will be zero!
An improper expression: 2 is an exponent. P = VI V = IR P = (IR)I P = I^2R
V2/r=p i2r=p vi=p
P = I2R Where: P = power loss I = current R = resistance
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P=I2R=(59mA)2(8.2kohms)= 28.5443W
The difference between brophytes and trachphtes is that i dont know..=p
spelling :P //I GOOGLE MO :P
V = IR, so an alternate would be P = I2R
there's no difference between them as they both are done on slopes.. :) :P
There are several equations for power. For example, the definition of power: P = work/time Specifically for electricity, the following equations are often used: P = I2R P = V2/R
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P = I2R (power = current squared times resistance). Therefore, if the current doubles, the amount of dissipated electrical energy will increase by a factor of 4.P = I2R (power = current squared times resistance). Therefore, if the current doubles, the amount of dissipated electrical energy will increase by a factor of 4.P = I2R (power = current squared times resistance). Therefore, if the current doubles, the amount of dissipated electrical energy will increase by a factor of 4.P = I2R (power = current squared times resistance). Therefore, if the current doubles, the amount of dissipated electrical energy will increase by a factor of 4.