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To find any term of a geometric sequence from another one you need the common ration between terms: t{n} = t{n-1} × r = t{1} × r^(n-1) where t{1} is the first term and n is the required term. It depends what was given in the geometric sequence ABOVE which you have not provided us. I suspect that along with the 10th term, some other term (t{k}) was given; in this case the common difference can be found: t{10} = 1536 = t{1} × r^9 t{k} = t{1} × r^(k-2) → t{10} ÷ t{k} = (t{1} × r^9) ÷ (t{1} × r^(k-1)) → t{10} ÷ t{k} = r^(10-k) → r = (t{10} ÷ t{k})^(1/(10-k)) Plugging in the values of t{10} (=1536), t{k} and {k} (the other given term (t{k}) and its term number (k) will give you the common ratio, from which you can then calculate the 11th term: t{11} = t(1) × r^9 = t{10} × r
get off the computer and do your work.
P=q/r* * * * *The correct answer is P = k*q/r where k is the constant of proportionality.
Suppose N is a perfect number. Then N cannot be a square number and so N has an even number of factors.Suppose the factors are f(1) =1, f(2), f(3), ... , f(k-1), f(k)=N.Furthermore f(r) * f(k+1-r) = N for r = 1, 2, ... k so that f(r) = N/f(k+1-r)which implies that 1/f(r) = f(k+1-r)/NThen 1/f(1) + 1/(f(2) + ... + 1/f(k)= f(k)/N + f(k-1)/N + ... + f(1)/N= [f(k) + f(k-1) + ... + f(1)] / N= 2N/N since, by definition, [f(k) + f(k-1) + ... + f(1)] = 2N
The square of r increased by a quantity that is fifty times the cube of k can be written as r squared + 50 (k cubed). It cannot be solved any further.
Most organisms lie on a continuum between r-strategists and K-strategists, and the octopus is one of those. The octopus lays a lot of eggs, typical of an r-strategist, but also invests parental care into its offspring, typical of a K-strategist.
no it is a k-strategist
Flamingos are K-strategists
Bees are not R-strategist. Bees are considered to be K-strategist because they live in stable environments and produce few offspring.
An r-strategist because r-strategists are small, have a shorter life span, and have many offspring. Examples would be spiders, mice, fish, bugs, ect.
k-Strategist but act like r-Strategists in many such as expansion.
A species characterized by having rapid development, high motility, and a high reproductive rate relative to a K-strategist.
it is a k
A K strategist or K species are animals with few, and often large offspring. The nurture and protect their young, reproduce later in life, live long, and population size is stable and near carrying capacity. Examples are elephants, humans, etc... A R strategist is something like insects and weeds.
An r-strategist produces more offspring, which can spread quite easily. In his way it can ensure a greater chance that at least some of t's offspring will survive, despite the possibility of environmental disturbances.
only retards ask that question you as.
Yes, r-strategist are known for reproducing quickly; humans can be classified as r-strategist as well.