To answer this question, you first need to find all the unique sets of 4 numbers that add up to 6. These are:
0006
0051
0042
0033
0411
0321
0222
3111
2211
Now we need to find which of these can be ordered to give numbers between 1111 and 9999:
0006: 6000
0051: 1500, 5001, 5010, 5100
0042: 2004, 2040, 2400, 4002, 4020, 4200
0033: 3003, 3030, 3300
0411: 1104, 1140, 1401, 1410, 4011, 4101, 4110
0321: 1203, 1230, 1302, 1320, 2013, 2031, 2103, 2130, 2301, 2310, 3012, 3021, 3102, 3120, 3201, 3210
0222: 2022, 2202, 2220
3111: 1113, 1131, 1311, 3111
2211: 1122, 1212, 1221, 2112, 2121, 2211
These are all the numbers between 1111 and 9999 with a digit sum of 6.
5,040
There are 28706 such combinations. 5456 of these comprise three 2-digit numbers, 19008 comprise two 2-digit numbers and two 1-digit numbers, 4158 comprise one 2-digit number and four 1-digit numbers and 84 comprise six 1-digit numbers.
Number of 7 digit combinations out of the 10 one-digit numbers = 120.
There are 900 three digit numbers between 99 and 3,000 - ranging from 100 to 999
You have seven different digits (symbols) to choose from, so you can form seven different one digit numbers and 7×7=72=49 different two digit numbers.
There are 7,290 different 4-digit numbers that can be formed from the digits 1-9 without repetition.
That would be the numbers in the form "32x" (where "x" can be any digit). In other words, ten numbers.
5,040
There are no 3 digit numbers between 0 and 9 because 0 and 9 are 1 digit numbers.
use the digit 1234to make two different numbers
There are 9 1-digit numbers and 16-2 digit numbers. So a 5 digit combination is obtained as:Five 1-digit numbers and no 2-digit numbers: 126 combinationsThree 1-digit numbers and one 2-digit number: 1344 combinationsOne 1-digit numbers and two 2-digit numbers: 1080 combinationsThat makes a total of 2550 combinations. This scheme does not differentiate between {13, 24, 5} and {1, 2, 3, 4, 5}. Adjusting for that would complicate the calculation considerably and reduce the number of combinations.
Any multiple of 36 will do. Multiply 36 by different numbers, until you get a 5-digit number.Any multiple of 36 will do. Multiply 36 by different numbers, until you get a 5-digit number.Any multiple of 36 will do. Multiply 36 by different numbers, until you get a 5-digit number.Any multiple of 36 will do. Multiply 36 by different numbers, until you get a 5-digit number.
the diffrenece between two 3 digit numbers is a palindrome between 200 and 300. what are the numbers?
There are 28706 such combinations. 5456 of these comprise three 2-digit numbers, 19008 comprise two 2-digit numbers and two 1-digit numbers, 4158 comprise one 2-digit number and four 1-digit numbers and 84 comprise six 1-digit numbers.
There are 360 of them.
You can select 12 numbers for the first digit, 11 numbers for the second digit, and 10 numbers for the third digit; so 12*11*10 = 1320 sets of 3 numbers can be made out of 12 different numbers.
There are 900 three-digit whole numbers between 1 and 1000